Can you prove this trig identity?

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Show that \displaystyle{\sum_{k=1}^{n-1}\sin\frac{km\pi}{n}\cot\frac{k\pi}{2n} = n-m}\quad\quad(m,n\in\mathbb{N}^+,\ m\le n)
 
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Why not start by applying the Euler formula

\cos \alpha= \frac{e^{i\alpha}+e^{-i\alpha}}{2},~\sin \alpha=\frac{e^{i\alpha}-e^{-i\alpha}}{2i}

What do you get then??
 
micromass said:
Why not start by applying the Euler formula
What do you get then??

Thanks micromass, not see real advantage yet...geometric sequence cannot be handled easily with double summation...
 
elimqiu said:
Show that \displaystyle{\sum_{k=1}^{n-1}\sin\frac{km\pi}{n}\cot\frac{k\pi}{2n} = n-m}\quad\quad(m,n\in\mathbb{N}^+,\ m\le n)

What is the context of the question? Is it for schoolwork?
 
berkeman said:
What is the context of the question? Is it for schoolwork?
It's a tool to prove

f(x)=a_1\sin x+\cdots+a_n\sin nx,\quad |f(x)|\le |\sin x|\quad (\forall x\in\mathbb{R})\implies |a_1+\cdots+a_n|\le 1

It's not fit for homework in any math course I guess:)
 
No one interested in a proof of such a pretty formula?
 

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