Here's a cute, well known problem (it's referred to as the "missing area problem").
Take a circle, and mark n points around the circumference of the circle NOT evenly spaced. Draw all secants connecting the points. How many areas does that divide the circle into? (If n were even and you spaced all points equally, all "diameters" would cross at the center. Moving some of the points slightly will move some secants off the diameter so you will have line crossing near the center, increasing the number of areas. The point of "NOT evenly spaced" is to get the maximum number of areas.)
For example if there is only one point, there are no secants and the circle remains 1 area.
If there are two points, there is one secant and the circle is divided into two area.
If there are three points, there are 3 secants, forming a triangle. There is the area inside the triangle and 3 areas between the there sides and the circle: total of 4 areas.
If there are 4 points, there are 6 secants, four forming a quadrilateral and 2 diagonals. The two diagonals divide the quadrilateral into 4 areas and we have the four areas between the sides and the circle: total of 8 areas.
If there are 5 points, it's harder to count but there are 16 areas.
There is, believe it or not a simple formula for the number of area given n points!
How many areas if there are 6 points? You can draw a picture and count the areas or use the formula: there are 31!
(Hey, I said it was a "missing area" problem.)
In case you were wondering with 7 points, you get 57 areas.