Can Zero Torque Occur if Angular Momentum and Velocity Vectors Aren't Parallel?

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Zero torque can occur even when the angular momentum and angular velocity vectors are not parallel, particularly in rigid body dynamics where the moment of inertia is represented as a 3x3 matrix. The relationship between angular momentum (L) and angular velocity (ω) does not require them to be collinear, especially in the absence of external torques. The scenario described does not indicate an error in calculations, as a constant angular velocity can still yield zero torque. Understanding the matrix representation of inertia is crucial for grasping these concepts. This confirms that the initial assumptions about torque and vector alignment may need reevaluation.
KBriggs
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Hey all,

I have a physics problem here and I have come across an odd scenario, I wonder if you could tell me if this means that I have the wrong answer.

I have an ideal bar rotating about an arbitrary axis. The angular velocity vector \omega is NOT colinear with the angular momentum vector. However, \omega is constant, so when I try to find the torque on the bar by using hte time dervitive of the angular momentum vector, I get 0.

My question is this: is it possible for there to be 0 torque on the bar if the angular momentum and angular velocity vectors are not parallel? Because I was under the impression that the only time when they were not parallel was when there was some applied torque, but I have done this problem using three different methods now, all with the same result.
 
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Hi, KBriggs,

In general, the relationship between L and w for a rigidly rotating body is not L=Iw, where I is a scalar; I has to be a 3x3 matrix. Even for an isolated body with no torques acting on it, it is not necessary for L and w to be collinear. Here is a discussion of this kind of thing that might help: http://www.lightandmatter.com/html_books/0sn/ch04/ch04.html#Section4.3

Ben
 
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Thanks

So getting 0 torque doesn't mean I went wrong somewhere.

I know about the matrix notation, but I am new to this stuff so I am getting a little lost in the definitions.
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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