Can't get my head around reduced mass (particle physics)

  • Thread starter Flucky
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User informed about mandatory use of homework template.
I know it's probably simple but I just don't understand reduced mass.

I am trying to work out the reduced mass of 4He+.

m = memN / me + mN

Can somebody please just explain step by step what I do. This is only a segment of a 1 mark question and I'm getting my knickers in a frustratingly twisty twist. I've looked at the other threads and websites but still no clue.

The answer needs to be 3.99... but I always end up with 0.99...
 

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Orodruin
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Normally you would need to expand more than that on your attempted solution, but I have a suspicion.

What are the units you are quoting your answers in? Atomic mass units? In that case, did you insert the mass of one nucleon instead of that of a helium nucleus?
 
  • #3
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Hi Orodruin

I'll give you the full question to give a better understanding-

Calculate the wavelength of the n = 4 → 3 transition in 4He+ to an accuracy of 4 significant figures. (R∞=109 737 cm-1.) (Fine structure effects can be neglected.)

Now the equation that I'd use for this is:


[itex] \frac{1}{λ} = \frac{m}{m_e} R_∞ (\frac{1}{n_1^2} - \frac{1}{n_2^2})[/itex]

Where λ is wavelength, m is the reduced mass, and [itex]R_∞[/itex] is Rydberg constant.

So I know the answer for the wavelength is 468.7 nm (I looked), and working backwards to try make sense of reduced mass I got m = 3.99.

I tried it in SI units using the mass in kg of an electron + 2 protons + 2 neutrons but it still didn't help.
 

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