there is a function [tex]\Psi =\frac{c}{\sqrt{r}}e^{\frac{-r}{b}}[/tex](adsbygoogle = window.adsbygoogle || []).push({});

find the probaility in [tex]\frac{b}{2}<r<\frac{3b}{2}\\[/tex] region

the rule states [tex]\int_{-\infty}^{+\infty}|\Psi|^2dv=1\\[/tex]

[tex]1=\int_{-\infty}^{+\infty}|\frac{c}{\sqrt{r}}e^{\frac{-r}{b}}|^2dv[/tex]

then they develop it as

[tex]c^2\int _{all space}\frac{1}{r}e^{\frac{-2r}{b}}2\pir^2dr=4\pic^2\int_{0}^{+\infty}re^{\frac{-2r}{b}}dr\\[/tex]

they as it because of spherical coordinates

but i cant see here the jacobian of spherical coordinates.

i cant see here the x,y,z transition to r ,theta,phi

i cant see it in the last equation

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# Homework Help: Cant understand integral tranasition to spherical coordinates

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