Can't use a simple integral properly-must be retarded

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The discussion centers on the proper application of integrals in calculating mass distribution along a line, specifically using the function f(x) = a*x, where 'a' is a constant. The initial misunderstanding involves treating f(x) as the total mass rather than recognizing it as the density at point x. The correct approach requires integrating the density function from 0 to c, resulting in the total mass being calculated as the integral of f(x) dx from 0 to c, rather than simply multiplying the density by the length of the line.

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I will show you my (obviously wrong) way of thinking when i have to apply an integral.
Please correct me where I'm wrong.

(imaginary question)
Suppose you have a mass distribution across a line, where the mass of each point is given by the equation f(x)=a*x (assume a is a constant)
find the total mass, if the line is c meters long (beginning @ x=0)

(My stupid train of thought)
We have to add up all the individual masses on the line.
so divide the line into n segments, calculate the mass for each one and add them up
f(x1)+f(x2)+...+f(xn)=
a*x1+a*x2+...+a*xn=
a(x1+x2+...+xn)=
a*c

What am i doing wrong?
(Besides the language use, I'm not a native and have little experience in such teminology)
 
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cantRemember said:
I will show you my (obviously wrong) way of thinking when i have to apply an integral.
Please correct me where I'm wrong.

(imaginary question)
Suppose you have a mass distribution across a line, where the mass of each point is given by the equation f(x)=a*x (assume a is a constant)
find the total mass, if the line is c meters long (beginning @ x=0)

(My stupid train of thought)
We have to add up all the individual masses on the line.
so divide the line into n segments, calculate the mass for each one and add them up
f(x1)+f(x2)+...+f(xn)=
a*x1+a*x2+...+a*xn=
a(x1+x2+...+xn)=
a*c

What am i doing wrong?
(Besides the language use, I'm not a native and have little experience in such teminology)

Mass at each point does not have much sense. Is not f(x) the density at point x? Then the mass dm of a line element around x is dm=f(x) dx and you have to integrate from 0 to c.

If f(x) means the mass from 0 to x, then the total mass at x=c is just f(c) :smile:

ehild
 
ehild said:
Mass at each point does not have much sense. Is not f(x) the density at point x? Then the mass dm of a line element around x is dm=f(x) dx and you have to integrate from 0 to c.

If f(x) means the mass from 0 to x, then the total mass at x=c is just f(c) :smile:

ehild

Thank you. But how can you define density in segments while you cannot define mass?
 
a(x1+x2+...+xn)=
a*c
......
(x1+x2+...+xn)≠c

x1=0
xcenter=c/2
xn=c
 
Last edited:
cantRemember said:
Thank you. But how can you define density in segments while you cannot define mass?
If you have a continuous line the mass of a point of it is zero.
But you can cut out a small length at position x, and measure the mass: it is Δm, and the length is Δx. The average linear density is Δm/Δx. If you cut out shorter and shorter pieces that ratio tends to the density at point x, to dm/dx = f(x). The total mass is the integral of f(x).

ehild
 
Last edited:
The linear density at point x, f(x), is the mass per unit length. Think of it as a chain.
 

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