- #1
MostlyHarmless
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- 15
Find that capacitance of the system consisting of 3 dielectrics w/ length, l=1.0m, width, w= 1.0m and depth, d= 1.0 CM. ##k_1=1.5, k_2=2, k_3=2.5## *dimensions of conducting plates not given*
Equations: Capacitance, ##C= Q/{\delta}V##
Field in the dielectrics
##E={\frac{\sigma}{k{\epsilon}_0}}##
I've found the fields in each dielectric, and the potential difference in each, but I'm getting hung up there. I've gotten down to, ##|{\delta}V|=({\frac{Q}{A{\epsilon}_0}})({\frac{1}{k_1}}+{\frac{1}{k_2}}+{\frac{1}{k_3}})##
My problem is, the A refers to the area of the conducting plate, but as i pointed out, nothing is said concerning dimensions of those plates.
Is there another method that does not care about the area that I'm missing?
Equations: Capacitance, ##C= Q/{\delta}V##
Field in the dielectrics
##E={\frac{\sigma}{k{\epsilon}_0}}##
I've found the fields in each dielectric, and the potential difference in each, but I'm getting hung up there. I've gotten down to, ##|{\delta}V|=({\frac{Q}{A{\epsilon}_0}})({\frac{1}{k_1}}+{\frac{1}{k_2}}+{\frac{1}{k_3}})##
My problem is, the A refers to the area of the conducting plate, but as i pointed out, nothing is said concerning dimensions of those plates.
Is there another method that does not care about the area that I'm missing?