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## Homework Statement

The question is at

http://dl.getdropbox.com/u/175564/capacitance.JPG [Broken]

## Homework Equations

Q = CV

C = [tex] \epsilon_{0} A / d [/tex]

## The Attempt at a Solution

The right solution is Q^2 / C that is (h).

I know that C is proportional to the inverse of the distance between plates.

Thus, I suggests that the capacitance should one third of the original value.

The other problem is to have a relation between capacitance and work.

I know W=Fd, where we get a relation to capacitance by d.

This suggests me that the work should one third of the work done with the initial distance between plates in the capacitor.

How would you solve the problem.

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