[SOLVED] Capacitance in series and parallel circuit 1. The problem statement, all variables and given/known data Determine the equivalent capacitance between A and B for the group of capacitors in the drawing. 2. Relevant equations Cseries = 1/Cs = 1/c1 + 1/c2 + ... Cparallel = Cp = C1 + C2 + ... 3. The attempt at a solution The 4 and 12 micro farad capacitors are in parallel, so Cp = 16mf. The other four are in series, so 1/5+1/24 = 1/C = 4.138mf (top) 1/6+1/8 = 1/C = 3.429mf (bottom) All of these are in series, so 1/4.138+1/3.429+1/16 = 1/c; c = 1.678mf This is not right. Where is my logic faulty?