# Capacitance of a Thundercloud

#### mathnoobie

1. The problem statement, all variables and given/known data
The charge center of a thundercloud, drifting 3.0km above the earth's surface, contains 20 C of negative charge.
Assuming the charge center has a radius of 1.0km Calculate the Capacitance of the system.

2. Relevant equations
C=8.85*(10^(-12))*A/d

Where A is the area, D is the separation distance

3. The attempt at a solution
Basically I just used the formula and plugged and chugged because of the large sizes, we can ignore the curvature and treat it as parallel plate capacitors.
8.85*10^(-12)*4∏(1000)^2/3000

This however gave me the wrong answer, I'm not really sure where to go from here since this path was wrong.

I hope there isn't a limit to how many questions you can ask in a day :P

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#### haruspex

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2018 Award
I don't think the large absolute sizes justify the flat plate approximation. The problem would be essentially the same if the 3km and 1km were replace by 3m and 1m. It's the ratio of these sizes that might justify such an approximation.
What you have here can be thought of either as a sphere and an infinite plate, or as two spheres, non-concentric.

#### mathnoobie

I don't think the large absolute sizes justify the flat plate approximation. The problem would be essentially the same if the 3km and 1km were replace by 3m and 1m. It's the ratio of these sizes that might justify such an approximation.
What you have here can be thought of either as a sphere and an infinite plate, or as two spheres, non-concentric.
I confirmed with my professor about a week ago that it is to be solved using the flat plate approximation. He normally doesn't reply on the weekends though so I figured I'd go on here for help. I can't think of any other path to take regarding this problem.

#### haruspex

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2018 Award
Sorry, I completely misunderstood the geometry. I thought the charge in the cloud was a sphere which you were approximating as flat. I see now it is intended to be a disc. Given that, I can find no flaw in your method. What is the 'correct' answer?

#### mathnoobie

Sorry, I completely misunderstood the geometry. I thought the charge in the cloud was a sphere which you were approximating as flat. I see now it is intended to be a disc. Given that, I can find no flaw in your method. What is the 'correct' answer?

My answer is 3.7*10^-8, when I punch it in the calculator.

#### haruspex

Homework Helper
Gold Member
2018 Award
So where does the 4 come from in 8.85*10^(-12)*4∏(1000)^2/3000?

#### mathnoobie

So where does the 4 come from in 8.85*10^(-12)*4∏(1000)^2/3000?
Oh no, I was geometrically incorrect, I've been working with so many spheres that I assumed this was a sphere in the math even though I knew it was a disc.

That fixes everything. Thank you!

"Capacitance of a Thundercloud"

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