Capacitance per unit length - two cylindrical conductors

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SUMMARY

The discussion focuses on calculating the capacitance per unit length of two cylindrical conductors separated by a distance \(d\) with a dielectric layer of relative permittivity \(\varepsilon_r\) and thickness \(a\). The derived formula for capacitance per unit length is \(C' = \frac{2\pi\varepsilon_0}{\frac{\ln(2)}{\varepsilon_r} + \frac{\ln\left(\frac{d-2a}{2a}\right)}{\varepsilon_r} + \frac{\ln\left(\frac{d-a}{d-2a}\right)}{\varepsilon_r}}\). The user questions the limits of integration used for voltage calculation, suspecting a discrepancy with the book's solution, which presents a different numerator in the capacitance formula.

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gruba
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Homework Statement


Two cylindrical conductors, of distance between them d and radius a (a<<d), have dielectric layer of relative permitivitty εr and thickness a. Calculate capacitance per unit length of this system.

Homework Equations


Capacitance per unit length, C'=Q'/U
Gauss law, cylindrical symmetry, E=Q'/(2πεr2)

The Attempt at a Solution


I have started with the equation C'=Q'/U.
Voltage integration limits: (a - 2a) + (2a - (d-2a)) + ((d-2a) - (d-a))
After calculating the partial integrals, voltage U is:
U=Q'(ln2/εr+ln((d-2a)/(2a))+ln((d-a)/(d-2a))/εr)

Applying voltage in the expression for capacitance per unit length gives
C'=2πε0/(ln2/εr+ln((d-2a)/(2a))+ln((d-a)/(d-2a))/εr)

In my books solution, in the numerator there is πε0 for C'.

Are my limits of integration for voltage correct? Maybe it is a mistake in books solution.
Thanks for replies.
 
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gruba said:
Voltage integration limits: (a - 2a) + (2a - (d-2a)) + ((d-2a) - (d-a))
I don't understand that part.

As far as I understand the problem statement, you have two separate "cables"? Then the problem does not have a cylinder symmetry. Otherwise: do you have a sketch of the layout?
 

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