Capacitance problem (verify answer)

  • Thread starter jayjay112
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  • #1
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Find the capacitance of a parrell plate capacitor in pF with A=0.04 m^2
distance of seperation between plates = 2mm relative permittivity of dielectric = 6
and permittivity of free space = 8.854x10^-12


C = (6)(8.854x10^-12)(0.04) / 0.002

= 1.06248x10^-9 F

in pF = 1062.48 pF

Thanks
 

Answers and Replies

  • #2
LowlyPion
Homework Helper
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Find the capacitance of a parrell plate capacitor in pF with A=0.04 m^2
distance of seperation between plates = 2mm relative permittivity of dielectric = 6
and permittivity of free space = 8.854x10^-12


C = (6)(8.854x10^-12)(0.04) / 0.002

= 1.06248x10^-9 F

in pF = 1062.48 pF

Thanks
You had it until you wrote the last answer.

1.062 pF
 
  • #3
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You had it until you wrote the last answer.

1.062 pF
But the answer 1.062x10^-9 isnt the same as 1.062x10^ -12 or 1.062 pF
 
  • #4
LowlyPion
Homework Helper
3,090
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But the answer 1.062x10^-9 isnt the same as 1.062x10^ -12 or 1.062 pF
But 1062 * 10-12 = 1.062 * 10-9

10-12 is pico, so sorry you are right. I confused nano-
 
  • #7
36
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But 1062 * 10-12 = 1.062 * 10-9

10-12 is pico, so sorry you are right. I confused nano-
no problem thanks again
 

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