Capacitance problem (verify answer)

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jayjay112
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Find the capacitance of a parrell plate capacitor in pF with A=0.04 m^2
distance of separation between plates = 2mm relative permittivity of dielectric = 6
and permittivity of free space = 8.854x10^-12


C = (6)(8.854x10^-12)(0.04) / 0.002

= 1.06248x10^-9 F

in pF = 1062.48 pF

Thanks
 
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jayjay112 said:
Find the capacitance of a parrell plate capacitor in pF with A=0.04 m^2
distance of separation between plates = 2mm relative permittivity of dielectric = 6
and permittivity of free space = 8.854x10^-12


C = (6)(8.854x10^-12)(0.04) / 0.002

= 1.06248x10^-9 F

in pF = 1062.48 pF

Thanks

You had it until you wrote the last answer.

1.062 pF
 
LowlyPion said:
You had it until you wrote the last answer.

1.062 pF

But the answer 1.062x10^-9 isn't the same as 1.062x10^ -12 or 1.062 pF
 
jayjay112 said:
But the answer 1.062x10^-9 isn't the same as 1.062x10^ -12 or 1.062 pF

But 1062 * 10-12 = 1.062 * 10-9

10-12 is pico, so sorry you are right. I confused nano-
 
LowlyPion said:
But 1062 * 10-12 = 1.062 * 10-9

10-12 is pico, so sorry you are right. I confused nano-

no problem thanks again