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Capacitance problem (verify answer)

  1. Apr 7, 2009 #1
    Find the capacitance of a parrell plate capacitor in pF with A=0.04 m^2
    distance of seperation between plates = 2mm relative permittivity of dielectric = 6
    and permittivity of free space = 8.854x10^-12


    C = (6)(8.854x10^-12)(0.04) / 0.002

    = 1.06248x10^-9 F

    in pF = 1062.48 pF

    Thanks
     
  2. jcsd
  3. Apr 7, 2009 #2

    LowlyPion

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    You had it until you wrote the last answer.

    1.062 pF
     
  4. Apr 7, 2009 #3
    But the answer 1.062x10^-9 isnt the same as 1.062x10^ -12 or 1.062 pF
     
  5. Apr 7, 2009 #4

    LowlyPion

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    But 1062 * 10-12 = 1.062 * 10-9

    10-12 is pico, so sorry you are right. I confused nano-
     
  6. Apr 7, 2009 #5

    pico is 10^ -12

    see link http://en.wikipedia.org/wiki/Pico-

    Thanks for your help with verifing my results.
     
  7. Apr 7, 2009 #6

    LowlyPion

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  8. Apr 7, 2009 #7
    no problem thanks again
     
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