Capacitors in Series: Finding Equivalent Capacitance and Stored Charge

[m_physics]

1. Two capacitors, one 7.5 µF the other 15 µF, are connected in series across a 12-V battery. (a) Find the equivalent capacitance of the two capacitors. (b) Which capacitor stores more charge? Explain. (c) Find the charge stored on each capacitor.
2. Cequiv = ∑C
C = Q/V
3. (a) Cequiv = 7.5µF + 15µF
Cequiv = 22.5µF

(b) Capacitors maintain an electric charge, so greater capacitance will hole more charge, resulting in a greater charge?

(c) C= Q/V
7.5µF = Q/12V
Q = 90 µC

15µF = Q/12V
Q = 180µC

Book Answer:
(a) 5.0µF
(b) Their charges are the same.
(c) 60µC

Not sure how they got there?

 

[m_physics]

Charges are the same because its in series. Sorry, read the question wrong, if I redo everything with series, it works. I swear it said parallel.