1. Two capacitors, one 7.5 µF the other 15 µF, are connected in series across a 12-V battery. (a) Find the equivalent capacitance of the two capacitors. (b) Which capacitor stores more charge? Explain. (c) Find the charge stored on each capacitor. 2. Cequiv = ∑C C = Q/V 3. (a) Cequiv = 7.5µF + 15µF Cequiv = 22.5µF (b) Capacitors maintain an electric charge, so greater capacitance will hole more charge, resulting in a greater charge? (c) C= Q/V 7.5µF = Q/12V Q = 90 µC 15µF = Q/12V Q = 180µC Book Answer: (a) 5.0µF (b) Their charges are the same. (c) 60µC Not sure how they got there?