The discussion focuses on calculating the capacitance of a capacitor with a power of 2000*e^(-jPi/2) connected to an AC voltage described by u(t)=282.84sin(314*t+Pi/4). The participant correctly identifies that the angular frequency (w) is 314 and utilizes the relationship P=U*I and capacitance formula C=1/Xc*w. They derive the reactance (Xc) using the equation Xc=u^2/P, but encounter difficulty in converting the sinusoidal voltage into a phasor format for further calculations.
PREREQUISITESElectrical engineers, students studying AC circuit theory, and professionals involved in power systems analysis will benefit from this discussion.
0fibonacci1 said:So I'm trying to solve this kind of problem And I got stuck. Capacitor with power 2000*e^(-jPi/2) and connected to voltage u(t)=282,84sin(314*t+Pi/4). Determine the capacity. I know power is P=U*I, capacitance is C = 1 / Xc*w, from that u(t) we have that w is 314, so rearraning equation P = u^2/Xc, Xc = u^2 / P. And from eulers identity e^(-jPi/2) is actually -j1, but still can't remove sin from u.