Capacitive level sensor for liquids

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SUMMARY

The discussion centers on the use of a capacitive level sensor for monitoring liquid levels in storage tanks. The sensor operates as a cylindrical capacitor with specific dimensions and dielectric properties of the liquid and its vapor. The derived formula for capacitance incorporates both the liquid and vapor dielectrics, leading to a comprehensive equation for capacitance based on the height of the liquid. The specific values for the tank dimensions and dielectric constants provided allow for the calculation of capacitance values when the tank is full and empty.

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  • Understanding of capacitive sensors and their operation principles
  • Familiarity with cylindrical capacitor equations
  • Knowledge of dielectric constants and their significance in capacitance
  • Basic algebra for manipulating equations and solving for variables
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Homework Statement



The quantity of liquid available in its storage tank is often monitored by a capacitive level sensor. This sensor is a vertically aligned cylindrical capacitor with outer and inner conductor radii Ra and Rb, whose length L spans the height of the tank. When a nonconducting liquid fills the tank to a height (h less than or equal to L) from the tank's bottom, the dielectric in the lower and upper region between the cylindrical conductors is the liquid (Kliq) and its vapor (Kv) respectively.

a) Determine a formula for the fraction F of the tank filled by liquid in terms of the level-sensor capacitance C
b) By connecting a capacitance-measuring instrument to the level sensor, F can be monitored. If L = 2.0m, Ra = 5.0mm, Rb = 4.5mm, Kliq = 1.4 and Kv = 1.0, what values of C (in pF) will correspond to the tank being completely full and completely empty?


Homework Equations



Capacitance for a cylinder: C = (2piεL)/ln(Ra/Rb)

and ε= Kε0

C=QV, Q is charge on the capacitor and V is potential difference between them

The Attempt at a Solution



I figured to treat the capacitor as 2 different cylindrical capacitors in parallel with different dielectrics in them.

C = Cliq + Cv
= (2piKliqε0h)/ln(Ra/Rb) + (2piK0(L-h)/ln(Ra/Rb)
after some simplification:
= (2piε0(hKliq - hKv + LKv)/ln(Ra/Rb)

I don't know how to get from an equation with h and L to F, since F is h/L.
 
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What if you divide both sides by L?
 

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