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Capacitor current in function of time

  1. Sep 2, 2011 #1
    In a circuit of 1 generator (U) 1 resistor (R) and one capacitor (C), how do I calculate the current i in function of time,
    as well as the energy dissipated by the resistor during the time the capacitor is charged?
     
  2. jcsd
  3. Sep 2, 2011 #2

    Integral

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    Sorry, you will need to show us some effort before you get any help.
     
  4. Sep 2, 2011 #3
    I have no idea on how to solve this.


    I would try to integrate I

    [itex]\int \frac{C.dV}{dt}[/itex]

    But V changes during time

    I think


    [itex]V = Q/C [/itex]
    [itex] V=U-R.i [/itex]


    and
    [itex]Q = \int I.dt [/itex]

    But how do I put all together?
     
    Last edited: Sep 2, 2011
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