What is the mistake in my series capacitors homework?

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SUMMARY

The discussion centers on the calculation of voltage in a series capacitor configuration. The user initially miscalculated the total voltage as Vtotal=V1+V2/2+V3/3, which is incorrect. The correct approach involves recognizing that for capacitors in series, the effective capacitance is given by 1/Cs = 1/C + 1/2C + 1/3C, resulting in Cs = 6C/11. Consequently, the total voltage can be expressed as V = (11/6)(Q/C), which simplifies to V1.

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V = q/c
so v = q/c + q/2c + q/3c
q/c(1+1/2+1/3)
q/c (11/6)
hope this helps
 
So total V is (11/6)q/c ? Can you explain how that is V1?
 
Instinctlol said:
So total V is (11/6)q/c ? Can you explain how that is V1?
I can't get you. Actually is 11/6 times the V
 
Capacitors are connected in series. So the effective capacitance is
1/Cs = 1/C + 1/2C + 1/3C
= 11/6C
Cs = 6C/11
Now substitute this value for C for the equation V = 11/6(Q/C) you ll get Q/C which is nothing but V or V1
Hope you got it now
 

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