adiphysics said:
Does the water approach the maximum height in a capillary tube with 0 velocity?I mean to say that does it go to the maximum height and just stop or perform simple harmonic motion ?Water is in equilibrium but velocity need not be 0 or is it(why?).The expression we derive for h should be for mean position then not for maximum height.
It's actually an interesting problem:
http://capfluidicslit.mme.pdx.edu/reference/Capillary%20Flow%20and%20Wetting/Capillary%20rise/Zhmud_JCIS2000_DynamicsOfCapillaryRise.pdf
To summarize, the fundamental equation, assuming Poiseuille flow, is
ρ[zz'' + (z')^2] = (2γcosθ)/r - (8ηzz')/r^2 - ρgz,
where ρ, η is the fluid density and viscosity, z the column height, r the radius of the tube, and ' means time derivative. There are two asymptotic solutions; the Lucas-Washburn equation (steady state) and the low viscosity limit (Quere equation).
The Lucas-Washburn equation asymptotes as t→∞ to z(t) = Z(1-exp(-Kt)), where Z is the 'final' height Z = 2γcosθ/ρgr and K is another constant. The Quere equation asymptotes to z(t) = at + bt^2+..., with a = √(2γcosθ/ρr) and b = -g/6.
At equilibrium, perturbations to the height (Z + ε(t)) follow ε'' + g/Z ε = 0 (simple harmonic motion) in the Quere limit, and a more complicated function if the full fundamental equation is used.