Car Tire Skidding: Deceleration with uk = 0.8

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SUMMARY

The discussion focuses on calculating the deceleration of a car with locked wheels skidding on a flat surface, given a coefficient of kinetic friction (uk) of 0.8. Using Newton's 2nd law, the deceleration can be determined by the formula a = -uk * g, where g is the acceleration due to gravity (approximately 9.81 m/s²). This results in a deceleration of approximately 7.848 m/s². The discussion emphasizes the importance of understanding the relationship between friction and motion in physics.

PREREQUISITES
  • Understanding of Newton's 2nd law of motion
  • Knowledge of the coefficient of kinetic friction
  • Familiarity with basic physics concepts such as acceleration and deceleration
  • Ability to perform calculations involving gravitational acceleration (g)
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  • Study the application of Newton's laws in real-world scenarios
  • Learn about the effects of different coefficients of friction on vehicle dynamics
  • Explore advanced topics in vehicle safety and braking systems
  • Research the physics of tire performance under various conditions
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Physics students, automotive engineers, and anyone interested in vehicle dynamics and safety performance analysis.

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Suppose that the coefficient of kinetic friction of the rubber of a car tire and the street is uk = 0.8. What is the deceleration of the car on a flat street if the driver brakes sharply, so all the wheels are locked and skidding?

I'm not sure how I am supposed to solve this if only the uk is provided?
 
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