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Cartesian 3D Vector Plotting Points?

  1. Feb 28, 2013 #1
    1. The problem statement, all variables and given/known data
    Plot the following point:
    B(-2,3,5)




    3. The attempt at a solution
    If I were to plot (-2,3,5), when I make my first movement of -2, it does not move anywhere on the y axis correct and when I am moving on my Y axis, There is no movement in the z axis?
     
  2. jcsd
  3. Feb 28, 2013 #2
    In Cartesian coordinates (-2,3,5) is the same thing as saying "-2 in the x-direction, 3 in the y-direction, and 5 in the z-direction". As movement in the x,y,z-directions don't affect the other directions, so yeah...although note that if you're moving on the y-axis, you're not only not moving on the z-axis, but you're also not moving on the x-axis.

    So it's "move -2 on the x-axis, move 3 on the y-axis, move 5 on the z-axis".
     
  4. Mar 1, 2013 #3
    Ok thank you, can you give me some help on this:

    What is the axis or plane these points would lie:

    (-3,0,0) (4,-2,0) and (0,3,-5)
     
  5. Mar 1, 2013 #4
    If you're unsure about how to plot a point in 3D space, I'm not too sure how I'm going to explain to you how to find the equation of a plane from three points.

    Open your calc 3 book and get to reading.

    The way I would do it is find a normal vector for the plane by taking a cross product of two vectors defined by those points and then dotting that normal vector with a vector in the plane and setting it to zero...

    You need to go and learn the material. The answer is 10x + 35y + 27z + 30 = 0, if you need to check yourself.
     
    Last edited: Mar 1, 2013
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