- #1

ArmavirMig

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## Homework Statement

I have a herd of sheep moving at 7 m/s. My dog is at rest 5m in front of the sheep and then accelerates at a rate of 3 m/s^2. how long does it take in seconds for the bulls to catch up to the cowgirl?

## Homework Equations

I have a feeling that t=square root of 2s/a is relevant. But I also think that they have to be equal to each other since they meet at some point. So the V_s is 7m/s and the S_d is 5m+S_s. I know the dog's accerlation is 3m/s^2 but I don't have time here.

## The Attempt at a Solution

I thought about calculating the dog's time as t=square root of 2s/a with s being 5. that gave me 1.8 seconds which i assume means 1.8 seconds ahead of the sheep but the sheep are going 7 m/s so that means that in 1.29 seconds they will catch up with the dog? Thanks for any clarification from the prospective helpers.