Cauchy's equation in terms of material acceleration

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SUMMARY

The discussion centers on transforming Cauchy's equation in terms of material acceleration, specifically the equation del . (rho*V V) = {V*del . (rho*V)} + {rho*(V . del)*V}. Participants confirm that this transformation involves applying the product rule for derivatives in vector calculus. The identity can be validated by expressing it in Cartesian component form, which simplifies the understanding of the relationship between the terms involved.

PREREQUISITES
  • Understanding of Cauchy's equation in continuum mechanics
  • Familiarity with vector calculus and dot products
  • Knowledge of material acceleration concepts
  • Ability to work with Cartesian coordinate systems
NEXT STEPS
  • Study the application of the product rule in vector calculus
  • Learn about Cauchy's equation and its implications in fluid dynamics
  • Explore tensor algebra, particularly second-order tensors
  • Practice transforming equations in Cartesian component form
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Students and professionals in physics, mechanical engineering, and applied mathematics who are working with continuum mechanics and vector calculus.

Adam Venter
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Does anyone know which formula is used or how to arrive at the righthand side of the equation below, which is the dot product of del and rho*a 2nd order tensor(V V).
. represents dot product
and X a vector quantity
This problem is in connection with transforming cauchy's equation in terms of the material acceleration

del . (rho*V V) = {V*del . (rho*V) } + {rho*(V . del)*V}

Thanks
 
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Adam Venter said:
Does anyone know which formula is used or how to arrive at the righthand side of the equation below, which is the dot product of del and rho*a 2nd order tensor(V V).
. represents dot product
and X a vector quantity
This problem is in connection with transforming cauchy's equation in terms of the material acceleration

del . (rho*V V) = {V*del . (rho*V) } + {rho*(V . del)*V}

Thanks
It's basically application of the derivative of a product rule in a situation in which you are dealing with vectors. The easiest way to prove to yourself that the identity is correct is to write it out in cartesian component form.

Chet
 
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Chestermiller said:
It's basically application of the derivative of a product rule in a situation in which you are dealing with vectors. The easiest way to prove to yourself that the identity is correct is to write it out in cartesian component form.

Chet
Thanks will give that a go
 

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