I Cavity resonances between two long parallel plates

AI Thread Summary
The discussion focuses on the impact of finite dimensions in the X-direction on the resonant wavelengths of acoustic waves between two parallel plates. When the plates are not infinitely long, new boundary conditions arise, particularly at the edges, which are now open to air, affecting the normal modes. The medium between the plates and the external air is the same, which leads to radiation losses that can wash out resonances. A normal mode analysis may not be entirely effective due to the lack of a fully enclosed cavity. The geometry's strong coupling to the outside world necessitates careful consideration of boundary conditions to accurately compute the normal modes.
nawidgc
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Consider two rigid and infinitely long parallel plates (say they are of infinite length in X direction, so running from -inf to +inf in X axis) separated by a distance d (say measured in Y-direction). Let the space between the plates be filled up with a fluid that supports acoustic waves. If we somehow setup the resonance of acoustic wave, the wavelengths corresponding to successive resonant modes are:

λ1 = 2d/1
λ2 = 2d/2
λ3 = 2d/3
and so on.

How does the wavelength change when the plates are no longer of infinite extent in X-direction? If the dimension in X-direction is of the same order as d, what effect would this have on the resonant frequencies/wavelengths?
 
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The boundary conditions will be changed. There are now edges or interfaces normal to x. What are these boundary conditions on these surfaces?
 
The surfaces normal to the x-direction are open to air outside whereas the plates themselves are rigid (normal component of particle velocity = 0).
 
And that air is a different fluid than the fluid between the plates ?
 
No - the medium between the plates and outside is the same, i.e., air.
 
BvU said:
And that air is a different fluid than the fluid between the plates ?
i suppose a normal mode analysis would not be useful as the cavity is not completely enclosed.
 
BvU said:
And that air is a different fluid than the fluid between the plates ?
Picture2.png
 
Paul Colby said:
You will have radiation losses.
Of course. So in that case, i would need to assume appropriate boundary condition at the exit surfaces of domain and compute the normal modes.
 
  • #10
nawidgc said:
Of course. So in that case, i would need to assume appropriate boundary condition at the exit surfaces of domain and compute the normal modes.
Depending on what accuracy you wish, yes. I would expect the geometry shown will have strong coupling to the outside world which will wash out the resonances. You might get some indication by assuming a perfectly absorbing x-boundary.
 

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