CDF ZZ Event Display: Lepton 1 Ambiguity

  • Thread starter Thread starter touqra
  • Start date Start date
  • Tags Tags
    Cdf Lepton
touqra
Messages
284
Reaction score
0
I was looking at this event display from CDF on their discovery of ZZ production. Why is lepton 1 having an ambiguity of either an electron or muon ?
http://fcdfwww.fnal.gov/physics/ewk/2007/ZZ/evd/r211311_e233113.html
 
Last edited by a moderator:
Physics news on Phys.org
I don't know the details of CDF electron identification, but I assume electrons are id'd based on calorimeter depositions, while muons depend on the muon chambers. If so, then the extra "debris" from the ppbar collision could have deposited enough energy in the calorimeter to pass the electron id. It is also possible that they are using this candidate even when one muon did not leave hits on the muon chambers (maybe went through a region without detector elements), in an attempt to increase the number of candidates on their sample.
 
Probably they label it e/mu because it is consistent both with the electron hypothesis (since it leaves some energy in the electromagnetic calorimeter, see the purple block) and with the muon hypothesis (since it has hits in the muon chambers).

My 2 cents: it is a muon which by chance is superimposed to a jet(*). There are three quite stiff tracks pointing in the same directions, which could justify the presence of a signal in the hadronic calorimeter (see the blue block over the purple block), and if it is a jet it's probable that you also have some neutral pions; neutral pions don't leave tracks but they decay into photons, and so give signal in the electromagnetic calorimeter.

(*) or maybe a jet from the fragmentation of a b quark, with the B meson decaying muonically. In this case this event would belong to the background and not to the signal.
 
Last edited:
ops, I essentially repeated the answer by ahrkron.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top