This question is actually posted up, but not under a very descriptive title so I'm reposting it and hoping the admin will just close my other one... sorry. Anyway, here is my problem-(adsbygoogle = window.adsbygoogle || []).push({});

#1) A typical lab centrifuge rotates at 4000rpm. Test tubes have to be placed into a centrifuge very carefully because of the very large accelerations. What is the acceleration at the end of a test tube that is 10cm from the axis of rotation in?

What I've already done is find the circumference of the circle, multiplied that by how many revs in a minute the lab does, divide that by 60 to get it in how many revs it does per second, then plug it into the centripetal acceleration equation a=(v^2)/r.

Work:

Known- 4000rpm, r=5cm

Find-a

4000rpm * (2pi(r=5)) = 1256.6m/min

1256.6/60 = 20.94m/s

a = ((v=20.94)^2)/(r=.05m) = 8772.98m/s^2

Obviously, this isn't right; so what do I need to do?

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# Homework Help: Centrifugal/Centripetal Acceleration

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