I Centrifugal Effects During Rail Launch

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The discussion focuses on the challenges of incorporating centrifugal effects from Earth's rotation in a 3DOF simulation for a rocket during its launch on a rail. It highlights the need to account for centripetal forces while the rocket is still constrained to the rail, particularly when launching in a west-east direction to leverage Earth's rotational speed. The Coriolis effect is also addressed, emphasizing its significance when the rail has a north-south component, as it alters the rocket's trajectory based on latitude. Participants discuss the complexities of managing these forces for various launch azimuths and sites. The conversation underscores the importance of accurately modeling these dynamics for effective simulation.
GrndCtrl2MjrTom
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TL;DR
Question about centrifugal effects on rocket during translation along a rail.
I’m writing a 3DOF sim for a rocket. I’m having a hard time visualizing centrifugal effects from the Earth's rotation on the rocket while it is moving along the rail (acceleration > 0).

I know that once it has left the rail I no longer need to account for it since it’s in the ECI frame and unconstrained with the earth. I’m just wondering how to deal with centrifugal effects during the rail launch since two of the body axes are still constrained.

I suppose I could rotate the centripetal ECEF components to the body coordinate frame and subtract out the roll component then I could rotate back to ECEF? Does this approach sound valid or am I missing something?
 
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If the rail is aligned in the west-east direction (I assume you would be sending the rocket on a west to east path to take advantage of the Earth's rotational speed), it is easy to work out the centripetal force required to keep it on the rail: ##F_c = \frac{mv^2}{R}## where v is the total speed of the rocket relative to the inertial frame of the centre of the Earth (ie. it includes the speed due to Earth rotation).

If there is a component of the rail that is in the north-south direction other than at the equator, you would have to take into account the Coriolis effect. The Coriolis effect (or force, if you are analysing it from the non-inertial rocket reference frame) arises if the rocket is moving in a direction other than parallel to the Earth's axis of rotation. This change results from the change in the rotational speed of the Earth surface/rail. The distance to the axis of rotation changes with change in latitude.

AM
 
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You are absolutely correct, thank you. I am trying to write this for any arbitrary launch azimuth and launch site, its just hard to remember everything that is acting on the rocket while on the ground haha.
 
Thread 'The rocket equation, one more time'
I already posted a similar thread a while ago, but this time I want to focus exclusively on one single point that is still not clear to me. I just came across this problem again in Modern Classical Mechanics by Helliwell and Sahakian. Their setup is exactly identical to the one that Taylor uses in Classical Mechanics: a rocket has mass m and velocity v at time t. At time ##t+\Delta t## it has (according to the textbooks) velocity ##v + \Delta v## and mass ##m+\Delta m##. Why not ##m -...

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