Centrifugal Force: Get Logical Explanation

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When an object moves in a circular path, it experiences an outward sensation often attributed to centrifugal force, which is actually a result of inertia and the need for centripetal force to maintain circular motion. In a rotating frame, such as a rotor, the wall exerts a real force against a person, counteracting the outward sensation felt due to inertia. This sensation is not a true force but rather a consequence of viewing motion from a non-inertial frame, where fictitious forces like centrifugal force appear. The coin on a rotating disk illustrates this principle; if friction is insufficient, it will slide outward due to inertia. Understanding these concepts clarifies the distinction between real forces and perceived forces in different frames of reference.
Wiz
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hi,
we all know tht when a body moves in a circular path,it experiences an outward force(eg:a coin on rotating disc gets thrown outward).Theoritically fine.But can anyone give me the LOGICAL explanation for this?Wht does it get thrown outward?

Also consider a person in a rotar standing with back touched to its wall...when the rotar starts rotating and the floor is moved down,the person does not fall since his weight is balanced by the frictional force which depends on the normal force.Which means that the person is exerting a force on the wall of the rotar..if centrifugal force is fictious then which force is this?..I am so deeply confused..
wiz
 
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A force is required to change the direction of an object (make it move in a circular path). That's the force that is felt.
 
There is no such thing as centrifugal force, its rather the lack of force that is felt.
 
What you actually feel, as Russ indicated, is the centripetal force that keeps you moving in a circle. In the rotor example, you feel the wall pushing against you--centripetal force. All this is perfectly understandable when viewed from the usual inertial frame; Newton's laws demand it.

The coin on the rotating disk is equally understandable: To keep the coin in place on the rotating disk requires a certain centripetal force; if the friction is insufficient, then the coin will tend to slide along its direction of motion. Inertia (Newton's 1st law) in action.

The so-called "fictitious" forces arise when one views things from a non-inertial, accelerating frame. In such a frame, Newton's law's don't apply without modification. The modification needed is the addition of inertial forces. In the rotor example, the wall exerts a "real" force against you ("real" just means that there is a real agent producing the force: the wall). To apply Newton's laws from the view of the rotating frame you must include the centrifugal force acting outwards: coupled with the force of the wall, the net force is zero.

But Eivind is correct that centrifugal force doesn't exist as a real force, it is only an artifact of using a noninertial frame of reference. But the effects are quite real.
 
Hello! Let's say I have a cavity resonant at 10 GHz with a Q factor of 1000. Given the Lorentzian shape of the cavity, I can also drive the cavity at, say 100 MHz. Of course the response will be very very weak, but non-zero given that the Loretzian shape never really reaches zero. I am trying to understand how are the magnetic and electric field distributions of the field at 100 MHz relative to the ones at 10 GHz? In particular, if inside the cavity I have some structure, such as 2 plates...

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