Centrifugal Force on a stone tied to a thread

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SUMMARY

The discussion centers on the concept of centrifugal force as it relates to a stone tied to a thread and spun in a circle. Participants clarify that when viewed from an inertial frame, the stone's tangential motion upon the thread breaking is due to inertia, as described by Newton's First Law, rather than centrifugal force. The centripetal force exerted by the string is acknowledged, while the idea of a reactive centrifugal force is debated, with emphasis on the distinction between real forces and pseudo forces in physics. The consensus is that all forces acting on the stone are directed toward the center of rotation.

PREREQUISITES
  • Understanding of Newton's Laws of Motion
  • Familiarity with inertial and non-inertial reference frames
  • Basic knowledge of centripetal force and its role in circular motion
  • Concept of reactive forces in physics
NEXT STEPS
  • Study the implications of Newton's First Law in circular motion scenarios
  • Explore the differences between real forces and pseudo forces in physics
  • Investigate the role of centripetal force in maintaining circular motion
  • Review case studies involving reactive forces in rotating systems
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of circular motion and the forces involved in rotating systems.

  • #31
AlephZero said:
If I ever get to be world dictator, my first act will be to execute everybody who has ever used terms like "reactive centrifugal force" as if they actually meant something :biggrin:
To me the "reactive"-part is more misleading than the "centrifugal"-part.
 
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  • #32
I think someone referred to a free body diagram. It should be the first requirement in discussions of this sort.
I would require my students to produce a free body diagram as part of the explanation of this elementary A level physics, you can tell at a glance whether they understand or not.
Let me offer my diagram.
C is the centripetal force. Can you identify the 3rd law pairings? (hint: they are different colours)
 

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  • #33
A.T. said:
Confusion of "force" and "net force" (as in F=ma). All the other wrong claims follow from that: That there are no outward forces, because there is no outward acceleration. That action & reaction in Newtons 3rd must be actual accelerations. And so on.

Ah ok, thanks for pointing out the issue. Yes as you say it is important to keep a distinction between individual forces and the net force.
 
  • #34
technician said:
I think someone referred to a free body diagram. It should be the first requirement in discussions of this sort.
I would require my students to produce a free body diagram as part of the explanation of this elementary A level physics, you can tell at a glance whether they understand or not.
Let me offer my diagram.
C is the centripetal force. Can you identify the 3rd law pairings? (hint: they are different colours)
It is somewhat arbitrary to speak about third law reaction pairs when what you have is an array of tensions, the existence of each of which depends all the existence of all the others.

We simplify things by treating the person and stone as point masses (located at the respective centres of mass) so we don't have to worry about analysing all the tensions within the person and within the stone. We also assume that the mass of the rope is negligible. If we do that, we can say, quite legitimately I think (although others on this board seem to disagree), that the stone is exerting a force on the person (via the rope) and the person is exerting an equal and opposite force on the stone. These can be considered third law force pairs in our simplified system. Each of those forces is toward the centre of rotation. There is no need to complicate matters by introducing the misleading, and - as far as I can tell - useless, concept of "centrifugal reaction force".

AM
 
  • #35
A.T. said:
As far I can say this is the core of the issue:Confusion of "force" and "net force" (as in F=ma). All the other wrong claims follow from that: That there are no outward forces, because there is no outward acceleration. That action & reaction in Newtons 3rd must be actual accelerations. And so on.
There is no confusion about net force. I never said that Newton third law pairs must be actual accelerations. A box resting on the Earth's surface undergoes no acceleration but the box and Earth are still exerting equal and opposite forces on each other (a pair of gravitational forces and a pair of mechanical forces).

What I have said (in another thread) is that Newton's third law is really about changes in motion (momentum conservation), not about static forces although I must admit that Newton was not very clear in his writing on this point. If Newton's third law is about changes in motion it becomes a universal law. If it is about equal and opposite tensions it is not universal. A good example of where the latter fails is in electrodynamics: a photon can exert a force on an atom but the atom cannot exert a force on the photon. However, there are always equal and opposite changes in momentum.

AM
 
  • #36
Andrew Mason said:
I disagree. "Centrifugal" has significant technical deficiencies. There is no possible way that the third law pair to the centripetal force on the stone will ever cause the rope to flee the centre of rotation. You have only to look at the Wikipedia article on "centrifugal reaction force" to see the confusion that surrounds that term.
That is not a technical objection, it is a semantic complaint. You cannot paint a rose with red color charge, you cannot win a woman's heart with a charm quark, there is no sense in which a top quark is on top, and so forth. You can object to those terms on similar grounds, but those are not technical deficiencies.

Anyway, we have already had this argument in full previously and I see nothing to be gained by rehashing it.
 

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