Centripetal acceleration! A jet flies in a vertical circle

1. Oct 27, 2012

hCornellier

1. The problem statement, all variables and given/known data
A pilot, whose mass is 96.0 kg, makes a loop-the-loop in a fast jet. Assume that the jet maintains a constant speed of 225 m/s and that the radius of the loop-the-loop is 2.064 km.

What is the apparent weight that the pilot feels (i.e., the force with which the pilot presses against the seat) at the bottom of the loop-the-loop?

What is the apparent weight felt at the top of the loop-the-loop?

2. Relevant equations
ac = v^2/r

3. The attempt at a solution
I've tried finding a solution for the bottom, but have yet to find it. I solved for Fg, (96kg*9.81m/s/s), then I found the centripetal force (point towards center of circle) to be equal to 2354.65N. I read that n-mg=ac?

2. Oct 27, 2012

jtpope2

you have the correct magnitudes for centripetal and gravitational force. you need to think about the direction of the force vectors and add them.

3. Oct 27, 2012

hCornellier

So the force exerted on the chair is equal to the centripetal force - Fg?

4. Oct 27, 2012

jtpope2

the vector for centripetal force always points towards the center and gravity points down, so add the vectors appropriately