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Centripetal acceleration! A jet flies in a vertical circle

  1. Oct 27, 2012 #1
    1. The problem statement, all variables and given/known data
    A pilot, whose mass is 96.0 kg, makes a loop-the-loop in a fast jet. Assume that the jet maintains a constant speed of 225 m/s and that the radius of the loop-the-loop is 2.064 km.

    What is the apparent weight that the pilot feels (i.e., the force with which the pilot presses against the seat) at the bottom of the loop-the-loop?

    What is the apparent weight felt at the top of the loop-the-loop?


    2. Relevant equations
    ac = v^2/r



    3. The attempt at a solution
    I've tried finding a solution for the bottom, but have yet to find it. I solved for Fg, (96kg*9.81m/s/s), then I found the centripetal force (point towards center of circle) to be equal to 2354.65N. I read that n-mg=ac?
     
  2. jcsd
  3. Oct 27, 2012 #2
    you have the correct magnitudes for centripetal and gravitational force. you need to think about the direction of the force vectors and add them.
     
  4. Oct 27, 2012 #3
    So the force exerted on the chair is equal to the centripetal force - Fg?
     
  5. Oct 27, 2012 #4
    the vector for centripetal force always points towards the center and gravity points down, so add the vectors appropriately
     
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