Centripetal acceleration A jet flies in a vertical circle

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SUMMARY

The discussion focuses on calculating the apparent weight of a pilot in a jet flying in a vertical loop. Given the pilot's mass of 96.0 kg, a constant speed of 225 m/s, and a loop radius of 2.064 km, the centripetal acceleration is determined using the formula ac = v^2/r. The apparent weight at the bottom of the loop is calculated by combining the centripetal force and gravitational force, while at the top, the forces must be appropriately vector-summed to find the resultant apparent weight.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula (ac = v^2/r)
  • Knowledge of gravitational force calculation (Fg = mg)
  • Familiarity with vector addition of forces
  • Basic physics principles related to circular motion
NEXT STEPS
  • Calculate the apparent weight at the top of the loop using vector addition of forces.
  • Explore the effects of varying speeds on centripetal acceleration in circular motion.
  • Investigate the implications of different loop radii on pilot forces in vertical loops.
  • Learn about the physiological effects of high g-forces on pilots during maneuvers.
USEFUL FOR

Aerospace engineers, physics students, and anyone interested in the dynamics of circular motion and the effects of acceleration on pilots in flight.

hCornellier
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Homework Statement


A pilot, whose mass is 96.0 kg, makes a loop-the-loop in a fast jet. Assume that the jet maintains a constant speed of 225 m/s and that the radius of the loop-the-loop is 2.064 km.

What is the apparent weight that the pilot feels (i.e., the force with which the pilot presses against the seat) at the bottom of the loop-the-loop?

What is the apparent weight felt at the top of the loop-the-loop?

Homework Equations


ac = v^2/r

The Attempt at a Solution


I've tried finding a solution for the bottom, but have yet to find it. I solved for Fg, (96kg*9.81m/s/s), then I found the centripetal force (point towards center of circle) to be equal to 2354.65N. I read that n-mg=ac?
 
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you have the correct magnitudes for centripetal and gravitational force. you need to think about the direction of the force vectors and add them.
 
So the force exerted on the chair is equal to the centripetal force - Fg?
 
the vector for centripetal force always points towards the center and gravity points down, so add the vectors appropriately
 

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