Centripetal Acceleration Question

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SUMMARY

The discussion centers on calculating the minimum velocity required for a skateboarder to complete a vertical loop with a radius of 6.53 m without falling off. The key equation used is centripetal acceleration, expressed as Ac = v^2 / r, where Ac is set to 9.8 m/s² to counteract gravitational force at the loop's apex. The skateboarder must maintain sufficient speed to ensure that the normal force approaches zero, allowing gravity to provide the necessary centripetal force. Understanding the interplay between centripetal force and gravity is crucial for grasping the dynamics of circular motion.

PREREQUISITES
  • Centripetal acceleration concepts
  • Basic physics of forces and motion
  • Understanding of free body diagrams
  • Knowledge of gravitational force (9.8 m/s²)
NEXT STEPS
  • Study the derivation of centripetal acceleration equations
  • Learn about free body diagrams in circular motion
  • Explore the effects of varying speeds on circular motion dynamics
  • Investigate real-world applications of centripetal force in roller coasters
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators seeking to explain the principles of centripetal acceleration and forces in a practical context.

Alameen Damer
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Homework Statement


A skateboarder has to do a loop the vertical loop of a roller coaster track. The radius of the loop is 6.53 m, what is the minimum velocity the skateboarder must have to not fall off when he is at the top of the loop.

Homework Equations


Equation for centripetal acceleration.

Ac=v^2 / r

The Attempt at a Solution


I know how to get the answer, basically rearranging for v, and setting Ac to 9.8 to counteract the gravity pulling the rider down. However, I need help understanding the concept. Why does setting the centripetal acceleration as 9.8 give you the right answer? In this case that the skateboarder is at the top of the loop, the gravity is pulling down in the same direction as the centripetal force. I'm pretty sure I am misunderstanding the direction of the centripetal force. Basically my question is: Does the centripetal force act in the same direction as gravity in this case?
 
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Alameen Damer said:
Basically my question is: Does the centripetal force act in the same direction as gravity in this case?
Yes , it does .
Alameen Damer said:
Why does setting the centripetal acceleration as 9.8 give you the right answer?
The normal force at the top must just tend to zero , for the boy to finish circular motion . Why ?
Hint : Because if the velocity would be zero , the force of gravity would do what ?
 
The gravity would simply pull down the boy, and he won't finish his loop
 
What I am confused on is if there is the force of gravity, in this case the centripetal force pulling down on the boy, what is the force that is counteracting it?
 
Alameen Damer said:
What I am confused on is if there is the force of gravity, in this case the centripetal force pulling down on the boy, what is the force that is counteracting it?
Gravity actually does pull the body during circular motion too , but only in the case of circular motion , it falls sideways .

I hope you can understand this .
 
What do you mean by it falls sideways? Do you mean that the net force cause the boy to continue on the loop rather than just fall off? If not, what is it that prevents the boy from just falling off at the top?
 
Alameen Damer said:
What do you mean by it falls sideways? Do you mean that the net force cause the boy to continue on the loop rather than just fall off?
Yes , this is it .
 
Ok thanks a lot!
 
Alameen Damer said:
Ok thanks a lot!
Have you tried drawing a free body diagram? What are the forces acting on the boy? What is the force balance equation?
 
  • #10
Alameen Damer said:
What do you mean by it falls sideways? Do you mean that the net force cause the boy to continue on the loop rather than just fall off? If not, what is it that prevents the boy from just falling off at the top?
Time. If the skateboarder's speed is just enough to do the loop, he is not at the top long enough for gravity to pull him down. Gravity has just enough time to deflect him from a straight line path so that he follows the curved rail at the top, but it does not have enough time to move him farther i.e to pull him away from the rail.

AM
 
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