Centripetal Acceleration with Tarzan

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SUMMARY

In the discussion regarding Tarzan's swing, it is established that the maximum speed he can tolerate at the lowest point of his swing is derived from the tension force exerted on the vine. Given Tarzan's mass of 100 kg and the force of 1200 N he can exert, the acceleration calculated is 4.20 m/s². The confusion regarding the radius of the swing is clarified; Tarzan orbits around the top of the tree, not the midpoint of the vine, which is 4.5 m long.

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  • Understanding of centripetal acceleration
  • Knowledge of Newton's second law of motion
  • Familiarity with tension force calculations
  • Basic principles of circular motion
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Homework Statement


Tarzan plans to cross a gorge by swinging in an arc from a hanging vine, as shown in the figure.
If his arms are capable of exerting a force of 1200 N on the vine, what is the maximum speed he can tolerate at the lowest point of his swing? His mass is 100 kg, and the vine is 4.5 m long.


Homework Equations


Tension force - mg = ma
(a * r)^1/2 = v


The Attempt at a Solution



1400 N = (100 kg)(a)+(100 kg)(9.8m/s^2)
420 N = 100kg * a
a = 4.20 m/s^2

(4.20 m/s^2)(2.25m)^1/2 = v

Why is it incorrect to use 2.25 m as the radius? They gave the entire length of the vine.
 

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If you look at the picture, what point is tarzan 'orbiting around' ?
 
BruceW said:
If you look at the picture, what point is tarzan 'orbiting around' ?

I lol'd

The picture reminds me of a picture on one of the exams I did a while back in high school, there's some bizarre half black half white basketball playing hybrid

Also, what BruceW said
 

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BruceW said:
If you look at the picture, what point is tarzan 'orbiting around' ?

Oh I see. That's more clear. He's orbiting around the very top of the tree, not the middle of the vine.
 

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