How Do You Calculate Centripetal Acceleration in a Blood Centrifuge?

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SUMMARY

The centripetal acceleration experienced by a sample in a blood centrifuge can be calculated using the formula a = v²/r, where v is the linear velocity and r is the radius from the rotation axis. In this discussion, the test tube is positioned at an angle of θ = 32.0° and spun at a rate of 4316 RPM. The final calculated centripetal acceleration at a point 9.93 cm from the rotation axis is 10749 m/s², which corresponds to approximately 1093.5 times the standard gravity (g).

PREREQUISITES
  • Understanding of centripetal acceleration and its formula a = v²/r
  • Knowledge of angular velocity and its relationship to linear velocity
  • Familiarity with unit conversions, particularly from RPM to seconds per revolution
  • Basic trigonometry to account for angles in physical calculations
NEXT STEPS
  • Learn about angular velocity and its calculation using the formula ω = 2πf
  • Study the effects of angle on centripetal acceleration in rotating systems
  • Explore the relationship between linear velocity and radius in circular motion
  • Investigate practical applications of centrifugation in laboratory settings
USEFUL FOR

Students in physics or engineering courses, laboratory technicians working with centrifuges, and anyone interested in the dynamics of rotating systems.

Jpyhsics
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Homework Statement


A centrifuge is a laboratory device used for spinning samples of material. In a blood centrifuge, a test tube is inserted at an angle θ=32.0° with respect to the vertical and the whole sample is spun at high speed. For a typical test that is l= 15.9 cm long and is spun in a centrifuge at a rate of 4316 rotations per minute, what is the centripetal acceleration experienced by the sample at a point x=9.93 cm from the rotation axis, as measured along the test tube? Express your answer in units of the standard gravity g. Thus, if your answer is 19.62 m/s2 = 2.00×9.81 m/s2, you would enter 2.00 into the box.

Homework Equations


a=v2/r
T=2πr/f
v=d/t

The Attempt at a Solution


First, I found the period
T=2π(15.9)/(4316/60)=1.3888
v=2π(9.93)/1.3888=71.9
a=(71.9)2/9.93

I don't think I did this correctly, as I didnt use the angle...
I have included a photo as well,
 

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Jpyhsics said:

Homework Equations


a=v2/r
T=2πr/f
v=d/t
The equation T=2πr/f cannot be correct as you can tell by doing a unit analysis of the equation.

3. The Attempt at a Solution
First, I found the period
T=2π(15.9)/(4316/60)=1.3888
v=2π(9.93)/1.3888=71.9
a=(71.9)2/9.93
You need to be clear on the meaning of r in the equations. You want the centripetal acceleration of a particular point in the test tube. Mark this point in your diagram and try to draw a representation of r in the diagram.
 
TSny said:
The equation T=2πr/f cannot be correct as you can tell by doing a unit analysis of the equation.You need to be clear on the meaning of r in the equations. You want the centripetal acceleration of a particular point in the test tube. Mark this point in your diagram and try to draw a representation of r in the diagram.
So how what formulas would I have to use?
I would assume ac=v2/r? but what about the period (T)?
 
Jpyhsics said:
So how what formulas would I have to use?
Would I use the 15.9cm?
 
Jpyhsics said:
So how what formulas would I have to use?
You should be able to solve it using your two equations

a=v2/r
v=d/t

But if you have learned how to write centripetal acceleration in terms of angular velocity ω, you might find that to be a quicker way to the answer.
 
Jpyhsics said:
but what about the period (T)?
If the test tube makes 4316 revolutions in one minute, how much time does it take for it to make one revolution?
 
TSny said:
If the test tube makes 4316 revolutions in one minute, how much time does it take for it to make one revolution?
0.0139s per rotation?
 
Jpyhsics said:
0.0139s per rotation?
Oh I see how the angle relates now. I got an answer of 10749 m/s2. Thank you so much for your help! :)
 
Jpyhsics said:
Oh I see how the angle relates now. I got an answer of 10749 m/s2. Thank you so much for your help! :)
I think your answer is correct. Good work.
 

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