Centripital F. : Solve for Velocity given ax and r

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To find the speed of an orbiter in a circular orbit just above a planet's surface, the gravitational acceleration is given as 1.88 m/s², and the planet's radius is 1.33 x 10^6 m. The equation used is a = v²/r, leading to the calculation of velocity. The initial attempt yielded a speed of 1547.255 m/s, but rounding the acceleration to 1.8 m/s² was noted as an error. The final advice was to redo the calculation with the correct acceleration value for accurate results.
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Homework Statement


Find the speed of an orbiter in a circular orbit that is just above the surface of a planet, given that the orbiter's acceleration is equal to the planet's gravitational acceleration of 1.88 m/s2. The radius of the planet is 1.33 x106 m.


Homework Equations


a=v2/r


The Attempt at a Solution



I have done : √(1,330,000 m * 1.8 m/s2)

with a result of 1547.255 m/s. I'm not sure what part I'm not comprehending -- thank you in advance for any light you can shed on this!
 
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subzero800 said:
I have done : √(1,330,000 m * 1.8 m/s2)

with a result of 1547.255 m/s. I'm not sure what part I'm not comprehending -- thank you in advance for any light you can shed on this!
Except for rounding off 1.88 m/s^2 to 1.8 for some reason, your work looks fine. Redo that calculation.
 
That was it, Thanks Doc!
 

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