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Centripital Force and Coefficient of Friction

  1. Nov 21, 2005 #1
    The problem:
    A 2.00 x [tex]10^3[/tex] kg car rounds a circular turn of radius 20.0 m. If the road is flat and the coefficient of static friction between the tires and the road is 0.70, how fast can the car go without skidding?
    I know that I must use the formula [tex]F_c[/tex]=[tex]\frac{mv^2_T}{r}[/tex]
    and so I come up with [tex]F_c=\frac{(2000)(v^2_T)}{20}[/tex]
    I have no idea how to incorporate the coefficient of friction into the equation (I know that I need to incorporate it into the left side of the equation, I simply don't know how).
     
  2. jcsd
  3. Nov 21, 2005 #2
    The friction force will be
    mg*coefficient of friction
     
  4. Nov 21, 2005 #3
    Thanks. I knew it was something simple but my mind was blanking out and I couldn't seem to remember the formula.
     
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