Centripital Force and Coefficient of Friction

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SUMMARY

The discussion focuses on calculating the maximum speed a 2,000 kg car can achieve while rounding a circular turn with a radius of 20.0 m, given a coefficient of static friction of 0.70. The centripetal force formula, F_c = mv^2/r, is utilized to determine the relationship between speed and friction. The frictional force, which prevents skidding, is calculated as F_friction = mg * coefficient of friction. By equating the centripetal force to the frictional force, the maximum speed can be derived definitively.

PREREQUISITES
  • Understanding of centripetal force and its formula
  • Knowledge of static friction and its coefficient
  • Basic algebra for solving equations
  • Familiarity with Newton's laws of motion
NEXT STEPS
  • Learn how to derive centripetal acceleration from circular motion principles
  • Study the relationship between frictional force and motion in circular paths
  • Explore real-world applications of centripetal force in automotive engineering
  • Investigate the effects of varying coefficients of friction on vehicle dynamics
USEFUL FOR

Physics students, automotive engineers, and anyone interested in understanding the dynamics of vehicles in circular motion.

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The problem:
A 2.00 x 10^3 kg car rounds a circular turn of radius 20.0 m. If the road is flat and the coefficient of static friction between the tires and the road is 0.70, how fast can the car go without skidding?
I know that I must use the formula F_c=\frac{mv^2_T}{r}
and so I come up with F_c=\frac{(2000)(v^2_T)}{20}
I have no idea how to incorporate the coefficient of friction into the equation (I know that I need to incorporate it into the left side of the equation, I simply don't know how).
 
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The friction force will be
mg*coefficient of friction
 
neo143 said:
The friction force will be
mg*coefficient of friction
Thanks. I knew it was something simple but my mind was blanking out and I couldn't seem to remember the formula.
 

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