Challenges in Integrating the Fourier Transform of a Complex Function

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SUMMARY

The discussion focuses on the integration of the Fourier Transform of a complex function, specifically the integral \(\frac{1}{2\pi}\int_{-\infty}^{\infty} e^{-itx} \frac{1}{a^2+x^2} \mathrm{d}x\), where 'a' is a constant. Participants highlight the use of the derivative of the arctangent function and substitutions leading to the integral \(\int_0^{\pi/2} \cos(t \tan x) \mathrm{d}x\). The challenge arises from the confusion regarding the integration variable, which is confirmed to be \(dx\) rather than \(dt\).

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hamsterman
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I'm trying to find [itex]\frac{1}{2\pi}\int \limits_{-\infty}^{\infty}e^{-itx}\frac{1}{a^2+x^2}\mathrm{d}x[/itex] where 'a' is a constant.

First I noticed that there is [itex]\frac {\partial \arctan x}{\partial x}[/itex] in this and using a substitute got [itex]\int \limits_0^{\pi / 2}\cos( t \tan x )\mathrm{d}x[/itex] with some constants in the gaps.
I then remember that I'm working in complex numbers, factored [itex]a^2+x^2[/itex] and got something essentially along the lines of [itex]\int \frac{e^x}{x}\mathrm{d}x[/itex], or maybe rather [itex]\int \limits_0^{\infty} \frac {\cos tx} {a - ix}\mathrm{d}x[/itex].

I can't integrate either.
 
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Your integral does not contain "dx" or "dt". Without that we cannot tell what integration you intend. Is the problem
[tex]\int \frac{e^{-itx}}{a^2+ x^2} dx[/tex]
or is it
[tex]\int \frac{e^{-itx}}{a^2+ x^2}dt[/tex]
?
 
Oh, sorry. It's dx. I'll fix it right away.
 

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