Challenging Math Problems for the Curious Mind

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Homework Help Overview

The discussion revolves around various challenging mathematical problems, primarily in calculus, real and complex analysis, and generating functions. Participants express interest in intriguing problems that stimulate thought and exploration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants propose problems ranging from proving properties of polygons to evaluating infinite series and differential equations. Some express uncertainty about their own problem-solving abilities, while others share their attempts at solving specific problems.

Discussion Status

The discussion features a variety of mathematical problems, with participants actively engaging in proposing and attempting to solve them. Some guidance is offered in the form of hints and partial solutions, but there is no clear consensus or resolution on the problems presented.

Contextual Notes

Some participants mention the context of homework or academic challenges, indicating that certain problems may require specific knowledge or techniques that not all participants may possess. There are also indications of playful or light-hearted engagement with the problems, such as humorous questions.

benorin
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Would someone please post a good problem (or at least an interesting one) for me to work on, say calculus, real/complex analysis, or some generating function stuff, or some problem anybody can understand but will scratch their head at? I really bored. Thanks for cherring me up,

-Ben
 
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If P is a polygon, prove that it cannot be the union of disjoint convex quadrilaterals, each of which has exactly one face that is also a face of P.
 
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A particle is moving on the line y=x^3 in the first quadrant starting from Origin at a speed dy/dx=1 unit per...time unit. ignore units. :p

Question is...find a formula for the angle formed by the x-axis and a line created by the Origin and the particle's position.

In all honesty I saw it before but I never took the time to solve it. I doubt i can however ... :(
 
Find the sum:

[tex] \sum_{i = 0}^{+\infty}<br /> \tan^{-1} \frac{1}{1 + x + x^2}[/tex]

(I think I have that right)
 
Hurkyl said:
Find the sum:

[tex] \sum_{i = 0}^{+\infty}<br /> \tan^{-1} \frac{1}{1 + x + x^2}[/tex]

(I think I have that right)

Quite easy: it is a diverging series ...
:rolleyes:
 
Hurkyl, do you mean [tex]\sum_{x = 0}^{+\infty}\tan^{-1} \frac{1}{1 + x + x^2}[/tex] ?
 
Yes, that one looks better!
 
Hurkyl,

[tex]\sum_{x = 0}^{+\infty}\tan^{-1} \frac{1}{1 + x + x^2} = \sum_{x = 0}^{+\infty}\tan^{-1} \frac{(x+1)-x}{1 + (x+1)x} = \sum_{x = 0}^{+\infty}\left( \tan^{-1}(x+1)-\tan^{-1}x\right) = \lim_{M\rightarrow\infty} \tan^{-1}(M+1)-\tan^{-1}(0)= \frac{\pi}{2}[/tex]

Thanks,
-Ben
 
Try with this.

Find the product

[tex]\prod_{k=1}^{\infty} \left( 1 + \frac{2}{k^2 + 7} \right)[/tex].
 
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  • #10
Well, I have a problem which currently bugs me (although I think I already solved it). Find the solution to the differential equation:

dv/dt = a*v+b*v^2.

It represents the movement of a particle with a velocity dependent friction force (which is proportional to v for small v and proportional to v^2 for large v). So the solution must be equal to the stokes case for small values of v and equal to the Newton case for large values of v, that´s how you can check if your answer is correct.

I made the problem up myself, so it might not be physically correct. But at least it´s a solvable DE which you can make into a linear first order ODE by substitution. Sorry for my english.
 
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  • #11
WigneRacah said:
Try with this.

Find the product

[tex]\prod_{k=1}^{\infty} \left( 1 + \frac{2}{k^2 + 7} \right)[/tex].

Since [tex]\frac{\sin \pi x}{\pi x}=\prod_{k=1}^{\infty} \left( 1-\frac{x^2}{k^2}\right) = \prod_{k=1}^{\infty} \frac{k^2-x^2}{k^2}[/tex] it follows that

[tex]\frac{y}{x}\frac{\sin \pi x}{\sin \pi y}= \prod_{k=1}^{\infty} \frac{k^2-x^2}{k^2-y^2}[/tex]

[tex]\prod_{k=1}^{\infty} \left( 1 + \frac{2}{k^2 + 7} \right) = \prod_{k=1}^{\infty} \frac{k^2+9}{k^2 + 7} = \frac{\sqrt{7}}{3}\frac{\sin 3\pi i}{\sin \sqrt{7}\pi i}[/tex]​

recall that [tex]\sin iz = i\mbox{sinh}z[/tex] to get the final value, namely

[tex]\boxed{\prod_{k=1}^{\infty} \left( 1 + \frac{2}{k^2 + 7} \right) = \frac{\sqrt{7}}{3}\frac{\mbox{sinh} 3\pi}{\mbox{sinh} \sqrt{7}\pi } = \frac{\sqrt{7}}{3}\frac{e^{3\pi}-e^{-3\pi} }{e^{\sqrt{7}\pi}-e^{-\sqrt{7}\pi} }}[/tex]​
 
  • #12
Wow! Are you studying math at the uni? Or how come you can solve all that?
 
  • #13
1. Prove from first principles that exp(x) is indeed (1+x/s)^s as s tends to infinity.

2. If M is a matrix over the complex numbers and Tr(M^r)=0 for all r show that all eigenvalues of M are zero.

3. If f is a function from C to C and the integral of f round any triangle is zero show that f is analytic/holomorphic.

4. What is the genus of the Riemann surface corresponding to w=sqrt((z-1)(z-2)(z-3)..(z-n))

5. Prove, using homology groups, the fundamental theorem of algebra. Hint, this is actually a fixed point theorem.

(Note: one of these is tricky, one of these probably requires more material than you've yet learnt.)
 
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  • #14
matt grime said:
1. Prove from first principles that exp(x) is indeed (1+x/s)^s as s tends to infinity.

I'll do the easy one (it was homework in grad real analysis with Papa Rudin).

I assume that we have the definition [tex]e^x=\sum_{k=0}^{\infty}\frac{x^k}{k!}[/tex].


Let [tex]f_{s}(x)=\left(1+\frac{x}{s}\right) ^s[/tex]. Define [tex](a)_{k}:=a(a-1)\cdots (a-k+1)[/tex] and [tex](a)_{0}=1[/tex] (that is put [tex](a)_{k}= \frac{\Gamma (a+1)}{\Gamma (a-k+1)}[/tex] for [tex]k\in\mathbb{N}[/tex]. Now notice that

[tex]f_{s}^{(k)}(x)=\frac{(s)_{k}}{s^k}\left(1+\frac{x}{s}\right) ^{s-k},[/tex] for [tex]k\in\mathbb{N}[/tex]​

hence

[tex]f_{s}^{(k)}(0)=\frac{(s)_{k}}{s^k}[/tex] for [tex]k\in\mathbb{N}[/tex]​

so that we have the MacClaurin Series for [tex]f_s(x)[/tex] as being

[tex]f_{s}(x)=\sum_{k=0}^{\infty}\frac{(s)_{k}}{k!}\left( \frac{x}{s}\right) ^{k}[/tex]​

Consider the quantity

[tex]\left|f_{s}(x)-e^x\right| = \left|\sum_{k=0}^{\infty}\frac{(s)_{k}}{k!}\left( \frac{x}{s}\right) ^{k}-\sum_{k=0}^{\infty}\frac{x^k}{k!} \right|= \left|\sum_{k=0}^{\infty} \frac{x^k}{k!}\left(\frac{(s)_{k}}{s^k}-1\right)\right|[/tex]
[tex]\leq \sum_{k=0}^{\infty} \frac{|x| ^k}{k!}\left|\frac{(s)_{k}}{s^k}-1\right|[/tex]​

and note that [tex](s)_{k}=s(s-1)\cdots (s-k+1) \sim s^k\mbox{ as }s\rightarrow\infty[/tex] so that we have [tex]\left|f_{s}(x)-e^x\right|\rightarrow 0, \mbox{ as }s\rightarrow\infty[/tex].
 
  • #15
derive a variation for the nambu-goto action!
 
  • #16
BTW, Hurkyl, this problem was PUTNAM 1986/A-3.

benorin said:
Hurkyl,

[tex]\sum_{x = 0}^{+\infty}\tan^{-1} \frac{1}{1 + x + x^2} = \sum_{x = 0}^{+\infty}\tan^{-1} \frac{(x+1)-x}{1 + (x+1)x} = \sum_{x = 0}^{+\infty}\left( \tan^{-1}(x+1)-\tan^{-1}x\right) = \lim_{M\rightarrow\infty} \tan^{-1}(M+1)-\tan^{-1}(0)= \frac{\pi}{2}[/tex]

Thanks,
-Ben
 
  • #17
Oh, I didn't know that!
 
  • #18
How much wood could a woodchuck chuck if a woodchuck could chuck wood?

Answer in terms of the variables x, y, and photons.

Then the cubed root of it.

This one's been bothering me personally.

Thanks.
 
  • #19
Ah, double posted my question.
 
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  • #20
benorin said:
Would someone please post a good problem (or at least an interesting one) for me to work on, say calculus, real/complex analysis, or some generating function stuff, or some problem anybody can understand but will scratch their head at? I really bored. Thanks for cherring me up,

-Ben
How about this one:

https://www.physicsforums.com/showthread.php?t=150136


:smile:
?
 

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