Change from polar to rectangular coordinates

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Homework Help Overview

The discussion revolves around converting equations from polar to rectangular coordinates, specifically addressing the relationship between the variables in these coordinate systems.

Discussion Character

  • Mathematical reasoning

Approaches and Questions Raised

  • Participants are examining the correctness of an equation derived from polar coordinates, with one participant questioning the formulation of terms involving sine and cosine. Others are exploring different manipulations of the equation to clarify the relationships between the variables.

Discussion Status

There is an active exchange of ideas, with participants providing alternative formulations and expressing appreciation for clarifications. Multiple interpretations of the equation are being explored, indicating a collaborative effort to understand the conversion process.

Contextual Notes

Participants are working within the constraints of homework guidelines, focusing on the mathematical relationships without providing complete solutions.

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Homework Statement



change from polar to rectangular coordinates

Homework Equations



[tex]\cos{theta}+r^2\sin{theta}=\tan{theta}[/tex]

The Attempt at a Solution



I got
[tex]x^2 + y^2 + x + y = \frac{y}{x}\sqrt{x^2+y^2}[/tex]

does that look right?
 
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Since [tex]r^2[/tex] is multiplied by [tex]\sin \theta[/tex] rather than added to it, shouldn't it be

[tex]x + (x^2 + y^2)y = \frac{y}{x}\sqrt{x^2 + y^2}[/tex]?
 
ooohh thanks
 
The simplest way to do this is to multiply the entire equation by r:
[tex]r cos(\theta)+ r^2(r sin(\theta))= r tan(\theta)= r \frac{r sin(\theta)}{r cos(\theta)}[/tex]
so
[tex]x+ (x^2+ y^2)y= \sqrt{x^2+ y^2}\frac{y}{x}[/tex]
 

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