Change in the internal energy of an isobaric process

Click For Summary
SUMMARY

The discussion centers on calculating the change in internal energy (ΔU) for an isobaric process involving 0.250 mol of carbon dioxide (CO2) gas. The gas is heated from 27.0°C to 127.0°C under a constant pressure of 1.00 atm. The correct formula for ΔU is ΔU = C_v*n*ΔT, where C_v must be in units of moles. The initial incorrect calculation of ΔU = 520J was due to using an incorrect value for C_v, which was not in the appropriate units. After correcting the value of C_v, the accurate ΔU was determined.

PREREQUISITES
  • Understanding of ideal gas laws
  • Knowledge of specific heat capacities (C_v) for gases
  • Familiarity with the first law of thermodynamics
  • Basic algebra for manipulating equations
NEXT STEPS
  • Research the specific heat capacity (C_v) values for various gases
  • Learn about the first law of thermodynamics and its applications
  • Explore isobaric and isochoric processes in thermodynamics
  • Study the ideal gas law and its implications in real-world scenarios
USEFUL FOR

This discussion is beneficial for students studying thermodynamics, particularly those focusing on gas behavior and energy calculations in physical chemistry or engineering contexts.

Stendhal
Messages
24
Reaction score
1

Homework Statement


A cylinder contains 0.250mol of carbon dioxide (CO2) gas at a temperature of 27.0∘C. The cylinder is provided with a frictionless piston, which maintains a constant pressure of 1.00atm on the gas. The gas is heated until its temperature increases to 127.0∘C. Assume that the CO2 may be treated as an ideal gas.

Homework Equations


ΔU = ΔQ -W

ΔU = C_v*n*ΔT

The Attempt at a Solution


In this case, I thought that ΔU could be set equal to (5/2)nRΔT since we know all of those variables. The value I got for that was ΔU = 520J, but that isn't the correct answer. Any help in explaining where I am going wrong would be appreciated greatly!
 
Physics news on Phys.org
Did you look up the value of Cv on line or in the literature?
 
Whoops, to answer that, I did. The value I looked up however was not in units of moles, so I got the wrong answer. Found a value of Cv in moles and got the right answer.
 
  • Like
Likes   Reactions: Chestermiller

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 21 ·
Replies
21
Views
6K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K