Change in thermal energy of gas

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Homework Help Overview

The discussion revolves around the change in thermal energy of a gas during a compression process, where the gas is compressed from 600 cm³ to 200 cm³ at a constant pressure of 400 kPa, while 100 J of heat energy is transferred out of the gas.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the first law of thermodynamics, questioning the correct interpretation of work done on the gas and the signs associated with heat transfer and work. There are attempts to clarify the relationship between heat, work, and internal energy.

Discussion Status

Some participants have provided guidance on using the first law of thermodynamics, while others are exploring the implications of sign conventions for heat and work. There is an ongoing examination of whether the calculated change in thermal energy should be expressed as positive or negative.

Contextual Notes

Participants are navigating the conventions of thermodynamic signs and the implications of a negative change in thermal energy, particularly in relation to temperature changes.

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Homework Statement


A gas is compressed from 600cm3 to 200cm3 at a constant pressure of 400kPa . At the same time, 100J of heat energy is transferred out of the gas.

What is the change in thermal energy of the gas during this process?

Homework Equations


Express the answer in Joules.

Wgas=p(Vf-Vi)=p/\v


The Attempt at a Solution



400k(400cm.3)=p/\v

I came up with a wrong answer of 160 J. Any help would be appreciated.

Thanks,
Jared
 
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You calculated the work done on the gas not the change in thermal energy. What equation gives you the change in thermal energy of a gas?
 
I found the correct equation to use is Eth=Q-Wgas.

Alright. Eth=100J-160J = 60 J is that answer required to be in a positive or negative 60J?

Thanks,
Jared
 
Last edited:
Using the first law is the correct thing to do. It says ΔE = Q - W. You need to pay attention to the symbols and their signs. Is Q positive or negative? What about W? Positive or negative and why?
 
BTW, the sign on W is purely arbitrary. Thermodynamics has adopted the convention that W should be considered from the point of view of the gas: that is, the work done by the gas is W.
 
I am pretty certain the answer is -60J. Although, I don't feel confident that you can have a negative thermal energy change.

@ideasrule- I don't quite understand what you mean?
 
Remember that the internal energy depends on the temperature only. A negative thermal energy change means that the temperature drops.
 

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