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Change of internal energy of an ideal gas

  1. May 16, 2017 #1
    1. The problem statement, all variables and given/known data
    upload_2017-5-16_9-52-57.png

    2. Relevant equations
    Δu = ∫ [(a-Ru)+bT+cT^2+dT^3]dT

    3. The attempt at a solution

    The answer of 6447kJ/kmol is given but I am struggling to get to this answer after integrating the above formula and inserting the given values.

    Firstly would the integral of [(a-Ru)+bT+cT^2+dT^3]dT
    be:

    [(a-Ru)+bT^2/2+cT^3/3+dT^4/4] ?
     
  2. jcsd
  3. May 16, 2017 #2
    No. The first term should be (a-Ru)T.
     
  4. May 16, 2017 #3
    Is this because (a-Ru) is a constant?
    eg. ∫1 dx = x
     
  5. May 16, 2017 #4
  6. May 16, 2017 #5
    Thank you let me give that a try.
     
  7. May 16, 2017 #6
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