Charge density from electric flux density

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SUMMARY

The charge density, ρv, derived from the electric flux density vector \(\overrightarrow{D} = \hat{r}4rsin(\phi) + \hat{\phi}2rcos(\phi) + \hat{z}2z^{2}\), is calculated using the divergence operator: ρv = ∇·\(\vec{D}\). The correct expression for ρv is 2sin(φ) + 4z, after applying the appropriate partial derivatives. A crucial term, 4sin(φ), must be included in the calculation to ensure accuracy, particularly in the radial component of the divergence. This discussion emphasizes the importance of correctly applying the divergence in cylindrical coordinates.

PREREQUISITES
  • Understanding of electric flux density and its representation
  • Familiarity with the divergence operator in vector calculus
  • Knowledge of cylindrical coordinate systems
  • Basic proficiency in partial differentiation
NEXT STEPS
  • Study the application of the divergence operator in cylindrical coordinates
  • Learn about electric field and charge density relationships in electromagnetism
  • Explore advanced vector calculus techniques, including the use of divergence theorem
  • Review examples of calculating charge density from various electric flux density configurations
USEFUL FOR

Students in electromagnetism, physicists, and engineers working with electric fields and charge distributions will benefit from this discussion.

freezer
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Homework Statement



Determine the charge density due to the following electric flux density:

\overrightarrow{D} = \hat{r}4rsin(\phi ) + \hat{\phi}2rcos(\phi)+\hat{z}2z^{2}

Homework Equations



\rho _{v} = \triangledown \cdot \vec{D}

\rho _{v} = \frac{\partial }{\partial r} + \frac{\partial }{\partial \phi}+ \frac{\partial }{\partial z}

The Attempt at a Solution



\rho _{v} = \frac{\partial }{\partial r} 4rsin(\phi) + \frac{1}{r}\frac{\partial }{\partial \phi}2rcos(\phi)+ \frac{\partial }{\partial z}2z^{2}

\rho _{v} = 4sin(\phi)- 2sin(\phi) + 4z

\rho _{v} = 2sin(\phi) + 4z

does this look correct?
 
Last edited:
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freezer said:

Homework Statement



Determine the charge density due to the following electric flux density:

\overrightarrow{D} = \hat{r}4rsin(\phi ) + \hat{\phi}2rcos(\phi)+\hat{z}2z^{2}


Homework Equations



\rho _{v} = \triangledown \cdot \vec{D}

\rho _{v} = \frac{\partial }{\partial r} + \frac{\partial }{\partial \phi}+ \frac{\partial }{\partial z}

The Attempt at a Solution



\rho _{v} = \frac{\partial }{\partial r} 4rsin(\phi) + \frac{1}{r}\frac{\partial }{\partial \phi}2rcos(\phi)+ \frac{\partial }{\partial z}2z^{2}

does this look correct?

There is a term missing here.
 
rude man said:
There is a term missing here.

I am not seeing it. For cylindrical I am only seeing the 1/r on the phihat term
 
freezer said:
I am not seeing it. For cylindrical I am only seeing the 1/r on the phihat term

Stick a term 4sinø in there somewhere, anywhere. No partial derivative. Just that term. (It's part of the rhat coefficient: 4rsinø/r).
 

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