Charge on a bead given the Electric Potential

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SUMMARY

The discussion revolves around calculating the charge on a positively charged glass bead with a diameter of 1.80 mm, given a potential difference of 470 V between two points at distances of 1.80 mm and 4.00 mm from the bead. The user initially considers using the relationship V = E * ds to find the electric field and then applies the formula E = kq/r² to determine the charge. The correct approach involves using the potential difference formula PDiff = q/r₁ - q/r₂ to solve for the charge on the bead.

PREREQUISITES
  • Understanding of electric potential and electric field concepts
  • Familiarity with Coulomb's law and the constant k (Coulomb's constant)
  • Knowledge of the relationship between charge, distance, and electric potential
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study the derivation and application of the formula for electric potential difference
  • Learn about Coulomb's law and its implications in electrostatics
  • Explore the concept of electric fields generated by point charges
  • Practice problems involving charge calculations using different geometries
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in electrostatics and charge calculations, particularly in the context of homework or academic problem-solving.

julianne
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I currently have this problem for homework:

A 1.80 -diameter glass bead is positively charged. The potential difference between a point 1.80 from the bead and a point 4.00 from the bead is 470 . What is the charge on the bead?

And I cannot seam to get it. First I thought that I should relate the fact that V=E*ds to find electric field and then solve for the charge with the general equation E=kq/r^2.

Can anyone tell me if I am on the right track because I can't get the numbers to work.

Thank you for your help!
 
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Oh...and the measurements are all in milimeters!
 
Use PDiff=q/r_1-q/r_2.
 

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