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Homework Help: Charge on a bead given the Electric Potential

  1. Oct 1, 2007 #1
    I currently have this problem for homework:

    A 1.80 -diameter glass bead is positively charged. The potential difference between a point 1.80 from the bead and a point 4.00 from the bead is 470 . What is the charge on the bead?

    And I cannot seam to get it. First I thought that I should relate the fact that V=E*ds to find electric field and then solve for the charge with teh general equation E=kq/r^2.

    Can anyone tell me if I am on the right track because I can't get the numbers to work.

    Thank you for your help!
  2. jcsd
  3. Oct 1, 2007 #2
    Oh...and the measurements are all in milimeters!
  4. Oct 1, 2007 #3

    Meir Achuz

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    Gold Member

    Use PDiff=q/r_1-q/r_2.
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