julianne
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I currently have this problem for homework:
A 1.80 -diameter glass bead is positively charged. The potential difference between a point 1.80 from the bead and a point 4.00 from the bead is 470 . What is the charge on the bead?
And I cannot seam to get it. First I thought that I should relate the fact that V=E*ds to find electric field and then solve for the charge with the general equation E=kq/r^2.
Can anyone tell me if I am on the right track because I can't get the numbers to work.
Thank you for your help!
A 1.80 -diameter glass bead is positively charged. The potential difference between a point 1.80 from the bead and a point 4.00 from the bead is 470 . What is the charge on the bead?
And I cannot seam to get it. First I thought that I should relate the fact that V=E*ds to find electric field and then solve for the charge with the general equation E=kq/r^2.
Can anyone tell me if I am on the right track because I can't get the numbers to work.
Thank you for your help!