- #1
Physics2341313
- 53
- 0
Homework Statement
Consider the figure below, we need to find the charge on [itex]Q_0[/itex], both charges Q are negative. It is given that the net charge on [itex]Q_A[/itex] is zero.
The figure of the problem is attached.
The Attempt at a Solution
I understand how to get the solution except for one part. I'm just going to write [itex]F_x[/itex] and [itex]F_y[/itex] below to denote the forces components as the numbers aren't relevant (I don't think?) for my question.
I understand that we can discard the constant [itex] 1/4\pi\epsilon_0[/itex] or k whichever is preferred and that we can get rid of the [itex]a^2[/itex] terms in denominators when taking the radius and likewise for sin/cos for the respective components.
The solution is [itex] Q_0 Q/8 = \sqrt {F_x^2 + F_y^2}[/itex].
Now the solution is obtained by [itex]Q_0 = 8 * \sqrt {F_x^2 + F_y^2} [/itex]
Why is Q discarded here? I just don't see where it goes mathematically.. it just kind of "disappears". Is it discarded because it is stated that the net force caused by this charge is negligible?
Attachments
Last edited: