A uniform electric field is non zero in a 20x10m region at the surface of the earth. Determine the direction and magnitude of the total vertical deflection of the incoming charged particle by the time it exits the region. The charged particle is traveling horizontal through the electric field which is pointing down.
q= -10^-4 C
m= .01 kg
E = 500N/m downward.
F= qE + mg
a = qE/m
x = vt
The Attempt at a Solution
E, given in Newtons per meter is giving me problems.
I know the horizontal velocity is unchanged due to the perpendicular forces.
Vertical velocity and displacement can be found through kinematics when E is N/C.