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**1. The switch in the figure has been closed for a very long time.**

A.) What is the charge on the capacitor?

B.) The switch is opened at t = 0s. At what time has the charge on the capacitor decreased to 12% of its initial value?

A.) What is the charge on the capacitor?

B.) The switch is opened at t = 0s. At what time has the charge on the capacitor decreased to 12% of its initial value?

**2. Q=VC, tau= RC, etc.**

**3. A.) The capacitor will have a potential equal to Vbat = 100V. Q = VC = (100V)(2*10^-6 F) = 2*10^-4 C = 0.20 uC**

b.) e^-x = e^-(t/tau)

2.12*tau = t

2.12RC = t

2.12*70ohm*(2*10^-6F) = t = 30ms

b.) e^-x = e^-(t/tau)

2.12*tau = t

2.12RC = t

2.12*70ohm*(2*10^-6F) = t = 30ms