Charging an object by friction

In summary, Avijit is seeking to understand the 'triboelectric effect' and how much charge can be put on an object by rubbing it with a material such as fur. He specifically wants to know the approximate order of magnitude of the charge that can be expected on a 1 cm sphere made of thermocol. The charge will largely be carried on the surface of the sphere and can be calculated using the capacitance formula. The maximum charge that can be stored before it starts leaking out is dependent on the capacitance, which is determined by the size and shape of the object. The breakdown voltage of air also plays a role in determining the maximum charge that can be stored. Therefore, the type of material the sphere is made of does not
  • #1
avjt
5
0
Hi All.

I'm trying to get a quantitative sense of how much charge we can put on an object by rubbing: the 'triboelectric effect'.

To put it specifically, suppose I have a sphere of diameter 1 cm, made of thermocol (polystyrene). How much charge, approximately, can I reasonably expect to put on it by rubbing it with, say, some fur?

I'm looking for just an 'order of magnitude' -- like, is 1 microcoulomb reasonable? How about 10 uC? Or 100 uC? Or will it be lower -- like 100 nC or 10 nC...?

Thanks for the help...

Avijit
 
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  • #2
Odd as it may seem but your answer is not about the material your sphere is made of but its 'self capacitance' and the breakdown voltage of the surrounding air.

Since you mention coulombs I will do this in SI units.

Your sphere will carry its charge largely on the surface like a conductor even though it is an insulator. The capacitance of a conducting sphere is given by

C = 4 * Pi * epsilon * R where Pi =3.14 etc, epsilon is the permittivity of
space = 8.854.. * 10^-12 Farads / metre and R is the radius of the sphere in metres.

In practice you can charge the sphere to the breakdown voltage of air by repeated rubbing (think of a Van De Graaf generator). The breakdown voltage of air is 30 Kvolt per inch of radius of the smallest curvature of the discharging electrode as a rule of thumb
so V=3* 10^4 * R / (2.54 * 10^-2) if the radius of your sphere is in metres.

Lastly the charge in coulombs Q on a capacitance C charged to a voltage V is given by

C= Q/V so Q=C * V

Putting this all together you get

Q= (4 * Pi * epsilon * 3 *10^4)* R^2/(2.54 ^-2)

Putting in the numbers we get Q = 1.1 * 10^-4 * R^2

so for your 1 cm sphere we get Q= 1.1 * 10^-6 Coulombs ie 1.1 micro Coulombs

Note that this is the maximum as any surface roughness will greatly decrease this (the bumps have smaller radius of curvature to R in the above equation is reduced so greatly decreasing the charge.
 
  • #3
Thanks sambristol. Interesting to know that the charge will be independent of the material the ball is made of.

Cheers,

Avijit
 
  • #4
the charge a material can store depends upon the capacitance of that material ... that is how charge it can store before it starts leaking it out (in simpler terms) . u can keep on charging that object until it starts leaking the charges ...
the capacitance is all that matters and it only depends on the size and the shape of your object ...hope it helps ... :)

vishal
 
  • #5


I can provide some information on charging an object by friction. The amount of charge that can be transferred through friction, also known as the triboelectric effect, depends on several factors such as the materials involved, surface area, and the amount of force applied during rubbing.

In general, the triboelectric effect is a relatively weak form of charging compared to other methods such as induction or contact charging. The amount of charge transferred is typically in the range of nanocoulombs (nC) to microcoulombs (uC).

To give a more specific answer to your question, the amount of charge that can be transferred by rubbing a 1 cm diameter thermocol sphere with fur would likely be in the range of 10-100 nC. This is just an estimate and the actual amount may vary depending on the specific materials and conditions.

It is important to note that the triboelectric effect is not a precise method of charging and the amount of charge transferred can vary greatly. Additionally, the charge may dissipate quickly due to the insulating properties of the materials involved.

I hope this helps in your research on the triboelectric effect. Remember, the actual amount of charge transferred may vary and it is important to consider other methods of charging for more precise results.
 

1. How does charging an object by friction work?

Charging an object by friction involves rubbing two objects together, which causes the transfer of electrons from one object to the other. The object that gains electrons becomes negatively charged, while the object that loses electrons becomes positively charged.

2. What materials can be charged by friction?

Most materials can be charged by friction, but some materials are better at holding onto their electrons than others. Materials such as rubber, plastic, and fur are commonly used for charging by friction.

3. How do you know which object will become positively charged and which will become negatively charged?

The object that has a higher tendency to gain electrons will become negatively charged, while the object that has a lower tendency to lose electrons will become positively charged. This is known as the triboelectric series and can be used to predict the charge of objects after they have been rubbed together.

4. How can I tell if an object is charged by friction?

One way to tell if an object is charged by friction is by using an electroscope. If the object is charged, the leaves of the electroscope will either repel or attract each other. Another way is to use a balloon or a comb to see if they can attract small objects like paper or hair.

5. How long does the charge last after charging an object by friction?

The charge created by friction will eventually dissipate over time. The rate at which it dissipates depends on factors such as humidity and the materials involved. Generally, the charge will last for a few hours to a few days before it completely dissipates.

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