Check my solution please (Sine and cosine functions)

[supernova1203]

I was asked to draw the graph of y=cosx-2

This equation means the graph of y=cosx is shifted 2 units down correct? (Since -2 is the C value because if it were the d value in y=acos(k(x-d))+c it would be in degrees, so we shift each y coordinate down 2 units, or subtract the y value by 2, i have graped the equation, it makes sense but when i put it in the graphing calculator it shows a different graph, infact it shows y=cosx-2 to be the EXACT same graph as the one from y=cosx...

when i put those 2 equations in it shows 1 graph (or rather the 2 graphs on top of each other)
I suspect i am correct because my instincts never let me down and the graphing calculator probably has some settings wrong

who do you think is correct?

 

[LAHLH]

Yes, shift the y value down by 2 so that e.g. at x=0, instead of getting the peak at +1, it's now at -1.

 

[Mark44]

This seems to be the same question you asked in another thread. To get the graph of y = cos(x) - 2, shift the graph of y = cos(x) down by 2 units. You should not be getting the same graph for both functions.