Check my solution please (Sine and cosine functions)

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    Cosine Functions
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The discussion centers on the graph of the equation y=cos(x)-2, which represents a vertical shift of the standard cosine function downwards by 2 units. The user initially believes that the graphing calculator displays the same graph for both y=cos(x) and y=cos(x)-2, which is incorrect. The correct interpretation is that the peak of the cosine function at x=0 shifts from +1 to -1, confirming that the two graphs should not overlap. The consensus is that the user should verify the graphing calculator settings to ensure accurate representation.

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supernova1203
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I was asked to draw the graph of y=cosx-2

This equation means the graph of y=cosx is shifted 2 units down correct? (Since -2 is the C value because if it were the d value in y=acos(k(x-d))+c it would be in degrees, so we shift each y coordinate down 2 units, or subtract the y value by 2, i have graped the equation, it makes sense but when i put it in the graphing calculator it shows a different graph, infact it shows y=cosx-2 to be the EXACT same graph as the one from y=cosx...

when i put those 2 equations in it shows 1 graph (or rather the 2 graphs on top of each other)
I suspect i am correct because my instincts never let me down and the graphing calculator probably has some settings wrong

who do you think is correct?
 
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Yes, shift the y value down by 2 so that e.g. at x=0, instead of getting the peak at +1, it's now at -1.
 
This seems to be the same question you asked in another thread. To get the graph of y = cos(x) - 2, shift the graph of y = cos(x) down by 2 units. You should not be getting the same graph for both functions.
 

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