How can you use a table of values to graph y=cosx-2?

[supernova1203]

Graph the function y=cosx-2I have already graphed this, there are several methods to solve this, i opted to use table of values to find all the coordinates to y=cosx, then moved all the y coordinates of each point 2 units down, and the y int was at -1...would this method result in the correct graph?

the -2 is the c value I am assuming because the d value is ALWAYS in degrees, atleast in these instances.

y=asin(k(x-d))+c

y=acos(k(x-d))+c

what y int do you guys get? Does what i have done make sense?

this is to transform the function from base to y=cosx-2

 

[epenguin]

"I have already graphed this, there are several methods to solve this, i opted to use table of values to find all the coordinates to y=cosx, then moved all the y coordinates of each point 2 units down, and the y int was at -1...


would this method result in the correct graph? ...Does what i have done make sense?"

Yes. I don't know how you would get it really, or anything else, if it doesn't make sense.

Now I hope you will be confident to do the other ones and make sense.

 

[Mark44]

Graph the function y=cosx-2


I have already graphed this, there are several methods to solve this, i opted to use table of values to find all the coordinates to y=cosx, then moved all the y coordinates of each point 2 units down, and the y int was at -1...


would this method result in the correct graph?

Yes. If you know what the graph of y = f(x) looks like, the graph of y = f(x) - 2 will be the first graph translated (shifted) down by two units.

the -2 is the c value I am assuming because the d value is ALWAYS in degrees, atleast in these instances.

That's not generally true. The input values to the trig functions can be in degrees or radians, and rarely, grads, another kind of angle measure in which 100 grads make up a right angle.

y=asin(k(x-d))+c

y=acos(k(x-d))+c

what y int do you guys get? Does what i have done make sense?

this is to transform the function from base to y=cosx-2